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4 years ago

If a drop of blood is 0.05 mL, how many drops of blood are in a blood collection tube that holds 2 mL ?

Chemistry

2 answers:

soldi70 [24.7K]4 years ago

7 0

Just divide the two (2 / 0.05) and you will get your answer; there are 40 drops of bloodin the collection tube.

Drupady [299]4 years ago

7 0

Answer : The number of drops of blood in a blood collect in tube are, 40.

Explanation :

As we are given that:

Volume of a drop of blood = 0.05 mL

Volume of blood collection tube that holds = 2 mL

Now we have to calculate the number of drops of blood collect in tube.

$\text{Number of drops of blood}=\frac{\text{Volume of blood collect in a tube}}{\text{Volume of a drop of blood}}$

Now put all the given values in this expression, we get:

$\text{Number of drops of blood}=\frac{2mL}{0.05mL}=40$

Therefore, the number of drops of blood in a blood collect in tube are, 40.

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san4es73 [151]

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3 years ago

State the difference between sugar in water and pebbles in water

Usimov [2.4K]

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3 years ago

What is the quantity of heat (in kJ) associated with cooling 185.5 g of water from 25.60°C to ice at -10.70°C?Heat Capacity of S

Cerrena [4.2K]

Taking into account the definition of calorimetry, sensible heat and latent heat, the amount of heat required is 37.88 kJ.

<h3>Calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

<h3>Sensible heat</h3>

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

<h3>Latent heat</h3>

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

<u><em>25.60 °C to 0 °C</em></u>

First of all, you should know that the freezing point of water is 0°C. That is, at 0°C, water freezes and turns into ice.

So, you must lower the temperature from 25.60°C (in liquid state) to 0°C, in order to supply heat without changing state (sensible heat).

The amount of heat a body receives or transmits is determined by:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

c= Heat Capacity of Liquid= 4.184 $\frac{J}{gC}$
m= 185.5 g
ΔT= Tfinal - Tinitial= 0 °C - 25.60 °C= - 25.6 °C

Replacing:

Q1= 4.184 $\frac{J}{gC}$ × 185.5 g× (- 25.6 °C)

Solving:

<u><em>Change of state</em></u>

The heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to

Q = m×L

where L is called the latent heat of the substance and depends on the type of phase change.

In this case, you know:

n= 185.5 grams× $\frac{1mol}{18 grams}$ = 10.30 moles, where 18 $\frac{g}{mol}$ is the molar mass of water, that is, the amount of mass that a substance contains in one mole.