Answer:
Explanation:
Two moles of magnesium (Mg) and five moles of oxygen (O2) are placed in a reaction vessel. When magnesium is ignited, it reacts with oxygen. What is the limiting reactant in this experiment?
Mg + O2 → MgO (unbalanced)
first, balance the equation
2Mg +O2-------> 2MgO
two magnesium atoms react with one diatomic oxygen molecule
there is a 1:1 ratio of magnesium to oxygen atoms
but we have 2 moles of magnesium atoms and 2X5 = 10 moles of oxygen atoms
the lesser magnesium LIMITS the amount of product we can make, so it is the LIMITING REAGENT.
Answer:
The appropriate answer is "9.225 g".
Explanation:
Given:
Required level,
= 63 ppm
Initial concentration,
= 22 ppm
Now,
The amount of free SO₂ will be:
= 
= 
= 
The amount of free SO₂ to be added will be:
= 
= 
∵ 1000 mg = 1 g
So,
= 
= 
Thus,
"9.225 g" should be added.
Answer: Option (A) is the correct answer.
Explanation:
Nitrogen is a non-metal and it is known that non-metals do not conduct electricity. Thus, it will be least conductive out of the given options.
Whereas antimony (Sb) is a metalloid. Metalloid are the substance that show properties of both metals and non-metals. Thus, antimony will conduct electricity.
On the other hand, bismuth (Bi) is a metal hence, it will conduct electricity.
Thus, we can conclude that the order from least conductive to most conductive will be nitrogen (N), antimony (Sb), bismuth (Bi).
MgCl2 because it is the only option in which a metal appears with a nonmetal. In this case, the metal transfers electrons to the nonmental because the metal has a lower ionization energy.
Answer:
Explanation:
Percent yield is the ratio of the amount actually produced to how much could theoretically be produced. It is found using this formula:
For this reaction, the theoretical or expected yield is 325.0 grams. The actual yield is 123.8 grams.
Divide.
Round to the nearest hundredth. The 9 in the hundredth place tells us to round the 0 to a 1 .
The percent yield is about <u>38.1%</u>
