The histogram showing the number of events with the events cost is
misleading because;
- The x-axis scale shows the data is more clustered than it actually is
<h3>How can the histogram be analyzed?</h3>
Please find attached a possible diagram of the histogram in the question
created with MS Excel;
The data in the histogram is presented as follows;
![\begin{array}{|c|c|c}Event \ Cost&Number \ of \ Events\\1000- 1499&2\\1500-1999&4\\2000-2499&3\\3000-3499&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7B%7Cc%7Cc%7Cc%7DEvent%20%5C%20Cost%26Number%20%5C%20of%20%5C%20Events%5C%5C1000-%201499%262%5C%5C1500-1999%264%5C%5C2000-2499%263%5C%5C3000-3499%261%5Cend%7Barray%7D%5Cright%5D)
From the above table, we have that the class with event cost of 2000 to
2499 is left out, therefore, the data is more clustered.
The correct option is therefore;
<u>The x-axis scale shows the data is more clustered than it actually is</u>
Learn more about histograms here:
brainly.com/question/1413492
Here is your equation:
![12x-5=127](https://tex.z-dn.net/?f=12x-5%3D127)
You're trying to find x, and to do that, the variable must be alone. That means you need to cancel out everything with it. The only thing with the variable 12x is -5. To cancel that out, you have to do the opposite of it, which is +5. Add 5 to both sides.
![12x-5+5=127+5 \\12x=132](https://tex.z-dn.net/?f=12x-5%2B5%3D127%2B5%20%5C%5C12x%3D132)
12x(12 times x) is equal to 132. You need to find x. You have to do the opposite of times 12, which is divide by 12. Divide both sides by 12.
![\frac{12x}{12} = \frac{132}{12} \\ \\x=11](https://tex.z-dn.net/?f=%5Cfrac%7B12x%7D%7B12%7D%20%3D%20%5Cfrac%7B132%7D%7B12%7D%20%5C%5C%20%5C%5Cx%3D11)
Your answer is x is equal to 11 ; x = 11
<em>If you have any questions, feel free to ask in the comments! :)</em>
Answer:
The input value that produces the same output value in both charts is 2.
Step-by-step explanation:
You are given two functions
and
with tables
![\begin{array}{cc}x&f(x)\\-3&3.5\\-2&3\\-1&2.5\\0&2\\1&1.5\\2&1\\3&0.5\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bcc%7Dx%26f%28x%29%5C%5C-3%263.5%5C%5C-2%263%5C%5C-1%262.5%5C%5C0%262%5C%5C1%261.5%5C%5C2%261%5C%5C3%260.5%5Cend%7Barray%7D)
and
![\begin{array}{cc}x&g(x)\\-3&\\-2&\\-1&\\0&\\1&\\2&\\3&\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bcc%7Dx%26g%28x%29%5C%5C-3%26%5C%5C-2%26%5C%5C-1%26%5C%5C0%26%5C%5C1%26%5C%5C2%26%5C%5C3%26%5Cend%7Barray%7D)
First, fill in the second table:
![g(-3)=2\cdot (-3)-3=-6-3=-9\\ \\g(-2)=2\cdot (-2)-3=-7\\ \\g(-1)=2\cdot (-1)-3=-5\\ \\g(0)=2\cdot 0-3=-3\\ \\g(1)=2\cdot 1-3=-1\\ \\g(2)=2\cdot 2-3=1\\ \\g(3)=2\cdot 3-3=3](https://tex.z-dn.net/?f=g%28-3%29%3D2%5Ccdot%20%28-3%29-3%3D-6-3%3D-9%5C%5C%20%5C%5Cg%28-2%29%3D2%5Ccdot%20%28-2%29-3%3D-7%5C%5C%20%5C%5Cg%28-1%29%3D2%5Ccdot%20%28-1%29-3%3D-5%5C%5C%20%5C%5Cg%280%29%3D2%5Ccdot%200-3%3D-3%5C%5C%20%5C%5Cg%281%29%3D2%5Ccdot%201-3%3D-1%5C%5C%20%5C%5Cg%282%29%3D2%5Ccdot%202-3%3D1%5C%5C%20%5C%5Cg%283%29%3D2%5Ccdot%203-3%3D3)
Hence, the second table is
![\begin{array}{cc}x&g(x)\\-3&-9\\-2&-7\\-1&-5\\0&-3\\1&-1\\2&1\\3&3\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bcc%7Dx%26g%28x%29%5C%5C-3%26-9%5C%5C-2%26-7%5C%5C-1%26-5%5C%5C0%26-3%5C%5C1%26-1%5C%5C2%261%5C%5C3%263%5Cend%7Barray%7D)
The input value that produces the same output value in both charts is 2.
Answer:
-5
Step-by-step explanation:
We need to eliminate 22, so x is alone.
2x+22=12
So we subtract 22 from both sides.
2x+22=12
-22 -22
2x=-10
Now we have to divide 2 on both sides so x is alone.
2x=-10
÷2. ÷2
x=-5
We can always check
2(-5)+22=12
-10+22=12
12=12