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zzz [600]
3 years ago
13

Im Timed Help Pls I need help with math problem

Mathematics
1 answer:
Nady [450]3 years ago
7 0

Answer:

35.36 i think

Step-by-step explanation:

40%x68=27.2

20%x27.2=5.44

27.2+5.44=32.64

68-32.64=35.36

$35.36

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5
vitfil [10]

57+57+63

=177

no, there are more students than seats, (unless the players are included in the number?) in that case are there 27 players in a game? idk basketball, on the bench maybe?

7 0
3 years ago
Help me solve this please and thank you I will mark brainliest
Volgvan

Answer:

I am so sorry i cant help i cant see it properly and i need the points

Step-by-step explanation:

6 0
3 years ago
Given f(x)=2x^(3)-3x and g(x)=-3x^(2)+1, what is the value of h(3) where h(x)=(f+g)(x)?
tankabanditka [31]

Answer:girl u on your own for that question



Step-by-step explanation:


3 0
4 years ago
Assuming that the heights of college women are normally distributed with mean 64 inches and standard deviation 1.5 inches, what
professor190 [17]

Answer:

15.74% of women are between 65.5 inches and 68.5 inches.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 64, \sigma = 1.5

What percentage of women are between 65.5 inches and 68.5 inches?

This percentage is the pvalue of Z when X = 68.5 subtracted by the pvalue of Z when X = 65.5.

X = 68.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{68.5 - 64}{1.5}

Z = 3

Z = 3 has a pvalue of 0.9987

X = 65.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{65.5 - 64}{1.5}

Z = 1

Z = 1 has a pvalue of 0.8413

So 0.9987 - 0.8413 = 0.1574 = 15.74% of women are between 65.5 inches and 68.5 inches.

8 0
4 years ago
Find the solution of the system 2x-y=0 and 4x-2=2
yanalaym [24]

Answer:

(1, 2)

Step-by-step explanation:

2x-y=0

4x-2=2

-----------

y=2x-0

y=2x

-------------

4x=2+2=4

4x=4

x=4/4=1

---------------

y=2(1)=2

x=1, y=2.

8 0
3 years ago
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