Answer:
Ashleys age is 28.
Step-by-step explanation:
When finding numbers that are consecutive, I like to divide the sum in this case, 100 by the number of people or things, in this case, the 4 siblings. The sum is 100 and there are 4 of them so we divide them first.
100÷4=25 so our answer must be around there. The question states that the ages must be even. So the even numbers in the range of lets say 20-30 are 20, 22, 24, 26, 28 and 30. Closest four numbers to 25 are 22, 24, 26 and 28. We must have two numbers below 25 and two numbers above 25. So we will keep 22,24,26 and 28. If you add them together, then you'll get 100! Since we are looking for Ashley's age which is the oldest, her age will be 28 as 28 is the highest number out the four numbers (22,24,26,28)
Good Luck and hope this helped! <33
Answer: Sal used a debit card and paid a total of $324.80 for the stereo. (I took the test too)
Step-by-step explanation: Multiply $21.30 by 18 months. Then subtract the interest, $58.60, from the product because Sal paid immediately with a card which implies using a debit card. You get $324.80.
9514 1404 393
Answer:
- northbound: 2.5 hours
- southbound: 1.5 hours
Step-by-step explanation:
When the second train leaves the station, the trains are already 63 miles apart. The rate of increase of their separation is (57 +63) = 120 miles per hour. The remaining 243-63 = 180 miles of separation will be achieved in ...
(180 mi)/(120 mi/h) = 1.5 h
The northbound train will have traveled 2.5 hours; the southbound train will have traveled 1.5 hours when the trains are 243 miles apart.
Answer:
After 23 years , the capital will get three times as big
Step-by-step explanation:
Firstly, let us write the compound interest formula
P = I( 1 + r)^n
Since we are considering a capital rise of 3 times
If I, the initial value is x, the P
value later will be 3x
Interest rate is 5/100 = 0.05
so we need the value of t
This will be;
3x = x(1 + 0.05)^t
3= 1.05^t
ln 3 = t ln 1.05
t = ln 3/ln 1.05
t = 23 years
I would start off by taking away 1a. That would make the problem be 56ab3-35b.I only took away 1 because each have at least 1a and is okay to do.
Next I would deal with the variable b. I would cross of 1 b. That's because both sides have at least 1b. Now, it's shortened to be 56ab2-35.
Since you cannot take away anymore variables, you have to deal with 56 and 35. I start small with dividing each by 2. I am trying to see what the greatest number could be while making the numbers still be whole. That turns 56 into 28 when it's cut in half. The 35 now turns into 17.5.
I would assume your teacher would want the numbers to be whole. seeing as though when 35 is cut in half and makes a decimal number, I would leave them. What I mean by that is to leave the numbers as 56 and 35.
So, that means the answer is 56ab2-35.
I hope this helps!! (And makes sense)
