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5x = 2 + 6y
Divide both sides by 5
x = 6/5y + 2/5
Input in the other equation.
2.4 = .3(6/5y + 2/5) + .4y
2.4 = .36y + .12 + .4y
2.4 = .76y + .12
Subtract .12 from both sides.
2.28 = .76y
Divide both sides by .76
3 = y
x = 6/5(3) + 2/5
x = 18/5 + 2/5
x = 20/5 = 4
(4, 3)
<h3>(-3j²k³)²(2j²k)³</h3>
(-3j²k³)²(2j²k)³ = <em>When a power is raised to a power the exponents have to be multiplied.</em>
= (-3²j⁽²*²⁾k⁽³*²⁾)(2³j⁽²*³⁾k³) = <em>We can take out the constants</em>
= (9)(8)(j⁴k⁶)(j⁶k³) = <em>We can group the same variables</em>
= 72(j⁴j⁶)(k⁶k³) = <em>When multiplying two powers that have the same base, you have to add the exponents.</em>
= 72 j⁽⁴⁺⁶⁾k⁽⁶⁺³⁾ = 72j¹⁰k⁹
Answer = 72j¹⁰k⁹
Hope this helps!