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Amanda [17]
3 years ago
8

Hershey Park is a popular field trip destination. This year Peirce and Stetson both planned trips there. Peirce rented and fille

d 16 vans and 8 buses with 752 students. Stetson rented and filled 5 vans and 5 buses with 380 students. Each van and each bus carried the same number of students. How many students can a van carry? How many students can a bus carry?
Mathematics
2 answers:
Bingel [31]3 years ago
5 0
A can can holp 5 kids lol
serious [3.7K]3 years ago
3 0
A can can hold 18 kids! A bus can hold 58 kids!
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Can anyone help me with this question?
Andreyy89

Answer:

x= 60°, y = 80°, z = 40°

Step-by-step explanation:

Look at the line substending 40° and Z°; you would see that both lines are parallel and so their angles are they the same.

Hence z= 40° { corresponding angles of parallel lines}

Similarly;

Look at the line substending 60° and x°; you would see that both lines are parallel and so their angles are they the same.

60° = x° { corresponding angles of parallel lines}

Now looking at the angle between x and y; let's call the angle between them r

And you would observe closely that r = z° = 40°{ vertically opposite angles are equal}

Note that x + r + y = 180°{ angle on a straight line}

y = 180° - ( x + r)

y = 180 - (60+40)

y = 180° - 100°

= 80°

6 0
3 years ago
-4=x-15 show how you got the answer<br><br> A.) -4/15<br> B.) -19<br> C.) -60<br> D.) 11
8090 [49]
The answer is bee haha ha
4 0
3 years ago
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A machine that cuts corks for wine bottles operates in such a way that the distribution of the diameter of the corks produced is
Norma-Jean [14]

Answer:

A. P(x<3.85 or x>4.15)= P(x<3.85)+P(x>4.15) = 0.1336

Step-by-step explanation:

Working with an ordinary Normal Distribution of probability and trying to find the probabilities asked in it could be difficult, because there´s no easy method to find probabilities in a generic Normal Distribution (with mean μ=4 and STD σ=0.1). The recommended approach to this question is to use a process called "Normalize", this process let us translate the problem of any Normal Distribution to a Standard Normal Distribution (μ=0 and σ=1) where there´s easier ways to find probabilities in there. The "Normalization" goes as follows:

Suppose you want to know P(x<a) of the Normal Distribution you are working with:

P(x<a)=P( (x-μ)/σ < (a-μ)/σ )=P(z<b)   ( b=(a-μ)/σ )

Where μ is the mean and σ is the STD of your Normal Distribution. Notice P(z<b) now it´s a probability in a Standard Normal Distribution, now we can find it using the available method to do so. My favorite is a chart (It´s attached to this answer) that contains a lot of probabilities in a Standard Normal Distribution. Let´s solve this as an example

A. We want to find the probability of the cork being defective (P(x<3.85) + P(x>4.15)). Now we find those separated and, then, add them for our answer.

Let´s begin with P(x<3.85), we start by normalizing that probability:

P(x<3.85)= P( (x-μ)/σ < (3.85-4)/0.1 )= P(z<-1.5)

And now it´s time to use the chart, it works like this: If you want P(z<c) and the decimal expansion of c=a.bd... , then:

P(z<c)=(a.b , d)

Where (a.b , d) are the coordinates of the probability in the chart. Keep in mind that will only work with "<" (It won´t work directly with P(z>c)) and we will do some extra work in those cases.

P(z<-1.5) is in the coordinates (-1.5 , 0)

P(z<-1.5)= 0.0668

P(x<3.85)= 0.0668

Now we are looking for P(x>4.15), let´s Normalize it too:

P(x>4.15)=P( (x-μ)/σ < (4.15-4)/0.1 )=P(z>1.5)

But remember the chart only work with "<", so we need to use a property of probability:

P(z>1.5)= 1 - P(z<1.5)

Using the chart:

P(z<1.5)=0.9332                             (1.5 , 0)

P(z>1.5)= 1 - 0.9332

P(z>1.5)= 0.0668

P(x>4.15)= 0.0668

And our final answer will be:

P(x<3.85 or x>4.15)= P(x<3.85)+P(x>4.15) = 0.1336

4 0
3 years ago
-26 =3v +1 can i please get a answer
garik1379 [7]

Answer:

v = -9

Step-by-step explanation:

ur welcome

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I gotchu fam, a rotation is occurring and we know this because it’s rotating 180°. Figures PQRS and P’Q’R’S’ are congruent because they are the same shape and size, just in different places.
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