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tino4ka555 [31]

3 years ago

9

On a sunny day, a building and its shadow form the sides of a right triangle. If the hypotenuse is 34 m long and the shadow is 2

4 m, how tall is the building

2 answers:

worty [1.4K]3 years ago

6 0

Answer:

67 ft

Step-by-step explanation:

NeX [460]3 years ago

3 0

Answer:

Step-by-step explanation:

h=√[34²-24²]=√[(34-24)(34+24)]=√[10×58]=√(5×29)=√145 ≈12 m

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Natali [406]

Answer:

83.2 miles

Step-by-step explanation:

what i had to do was multiply 7.3 by 13 and that was 94.9 that was as close as i could get it to 100 so i then multipled 6.4 by 13 and got 83,2 miles

5 0

2 years ago

Evaluate the expression when a=-6 and c= 2 .<br> a-4c

Harman [31]

Answer:

-14

Step-by-step explanation:

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5 0

3 years ago

Read 2 more answers

Consider the half of the sphere of radius 2 centered at the origin which lies above the xy-plane (a hemisphere). Suppose the den

Harlamova29_29 [7]

Answer:

25.133 units

Step-by-step explanation:

Since the density ρ = r, our mass is

m = ∫∫∫r³sinθdΦdrdθ. We integrate from θ = 0 to π (since it is a hemisphere), Φ = 0 to 2π and r = 0 to 2 and the maximum values of r = 2 in those directions. So

m =∫∫[∫r³sinθdΦ]drdθ

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m = 25.133 units

5 0

3 years ago

Find the eighth term of the

Pie

Answer:

see explanation

Step-by-step explanation:

The n th term of a geometric sequence is

$a_{n}$ = a₁ $(r)^{n-1}$

where a₁ is the first term and r the common ratio, hence

$a_{8}$ = 6 × $(-1/3)^{7}$ = 6 × - $\frac{1}{3^{7} }$ = 6 × - $\frac{1}{2187}$ = - $\frac{2}{729}$

7 0

3 years ago

Quadrilateral KLMN has vertices of K(-4,-1), L(-1,-1) M(-2,-5) and N(-4,-4) Find the length of MN

Olenka [21]

Answer:

The length of MN is $\sqrt{5}$ units.

Step-by-step explanation:

The given Quadrilateral KLMN has vertices at K(-4,-1), L(-1,-1) M(-2,-5) and N(-4,-4).

We use the distance formula to find the length of MN.

$|MN|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We plug in the values to get

$|MN|=\sqrt{(-4--2)^2+(-4--5)^2}$

$|MN|=\sqrt{(-2)^2+(1)^2}$

$|MN|=\sqrt{4+1}$

$|MN|=\sqrt{5}$

The length of MN is $\sqrt{5}$ units.

3 0

4 years ago