Explanation:
Number of moles(n)=Number of atoms(N)/Avogadro's constant.
Avogadro's constant=6.02×10²³
so we have
n=9.05×10²³/6.02×10²³
n=1.0503moles.
n=mass/molar mass
1.0503=mass/28
mass=1.0503×28
mass=29.4084g
Answer:
B
Explanation:
because B has a lower bp it needs less time and energy to turn into vapour and is collected into the condenser first
<span>According to Faraday's Law,
W = I t e / F
Where,
W = Amount deposited = ?
I = Current = 3 A
t = Time = 965 s
e = Chemical equivalence = 52/3 = 17.33
F = Faraday's Constant = 96500
Putting Values,
W = (3 × 965 × 17.33) ÷ 96500
W = (50170.35) ÷ 96500
W = 0.52 g
As we know,
Moles = mass ÷ M.mass
Putting values,
Moles = 0.52 ÷ 52
Moles = 0.01</span>
When we assume that our solvent is water with total weight 100 g:
so we need to get the mass of K2SO3:
mass of K2SO3 = moles K2SO3 * Mw of K2SO3
now we need to get first the Mw of K2SO3 = 2*39 + 1*32 + 3*16 = 158 g/mol
by substitution:
∴ mass of K2SO3 = 0.0328 moles * 158 g/mol = 5.18 g
∴the mass of water = 100 g - 5.18 g = 94.8 g
∴ moles of water = mass of water / Mw of water
= 94.8 g / 18 g/mol
= 5.2 moles
∴the total moles = moles of water + moles of K2SO3
= 5.2 + 0.0328 = 5.266 moles
∴ the weight/weight % of K2SO3 = moles of K2SO3 / total moles*100
= 0.0325 moles / 5.266 moles *100
= 0.0062 *100
= 0.62 %
Answer:
S + 4 Cl2
Explanation:
Sulphur - S
1 mol of Sulphur = S
Chlorine = Cl2
4 moles of Chlorine = 4Cl2
4S + 2Cl2
Incorrect option
S + 4 Cl2
Correct option
S + 2Cl2
Incorrect option
S + Cl2
Incorrect option