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ololo11 [35]
3 years ago
10

Two molecules that can cross a lipid bilayer without help from membrane proteins are o2 and co2. what property allows this to oc

cur?
Chemistry
1 answer:
Dennis_Churaev [7]3 years ago
4 0
Two molecules that can cross a lipid bilayer without help from membrane proteins are oxygen and carbon dioxide. The property that allows this to happen is that both oxygen and carbon dioxide molecules are nonpolar which means that they can pass easily through the hydrophobic part of the membrane. The lipid bilayer is present in all cell membranes. It consists of two layers of the fat cells which are arranged into two sheets. It functions as a barrier which marks the boundaries of the cell. The inner part of a lipid bilayer is nonpolar since it is composed of the hydrophobic end of the phospholopids. 
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Which of the following is a type of kinetic energy.
dexar [7]
Kinetic energy is energy in motion. B, a rolling ball would be your answer because a rolling ball is energy that is moving. The rest of the answers are wrong because the actions do not use kinetic energy.
6 0
2 years ago
Is the capacity to do work or to produce heat.
antiseptic1488 [7]

Answer:

Energy is the ability to do work or to produce heat.

5 0
3 years ago
A sample of octane undergoes combustion according to the equation 2 C8H18 + 25 O2 → 16 CO2 + 18 H2O ΔH°rxn = -11018 kJ. What mas
Anna71 [15]

Answer:

\large \boxed{\text{528.7 g} }

Explanation:

It often helps to write the heat as if it were a reactant or a product in the thermochemical equation.

Then you can consider it to be 11018 "moles" of "kJ"  

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

M_r:                      32.00

              2C₈H₁₈ + 25O₂ ⟶ 16CO₂ + 8H₂O + 11 018 kJ

n/mol:                                                                  7280

1. Moles of O₂

The molar ratio is 25 mol O₂:11 018 kJ

\text{Moles of O}_{2} = \text{7280 kJ} \times \dfrac{\text{25 mol O}_{2}}{\text{11 018 kJ}} = \text{16.52 mol O}_{2}

2. Mass of O₂

\text{Mass of C$_{8}$H}_{18} = \text{16.52 mol O}_{2} \times \dfrac{\text{32.00 g O}_{2}}{\text{1 mol O}_{2}} = \textbf{528.6 g O}_{2}\\\text{The reaction requires $\large \boxed{\textbf{528.67 g O}_{2}}$}

3 0
3 years ago
What is the new boiling point if 25 g of NaCl is dissolved in 1.0 kg of water
Inessa05 [86]
The correct answer for the question that is being presented above is this one: 

Given that:
delta Tb = Kbm Kb H2O = 0.52 degrees C/m 
<span>delta Tf = Kfm Kf H2O = 1.86 degrees C/m 
</span>
We need to know the formula for Molality.
molality = mol solute / kg solvent 

<span>We are given the amount of solute in grams
Since amount of solute is given in moles, we have to convert 25 g NaCl to moles. Divide by molar mass. </span>

<span>25 g NaCl / 58.5 g/mol = 0.427 mol </span>

<span>Then, use the formula for molality. </span>

<span>molality = mol solute / kg solvent </span>
<span>= 0.427 / 1 </span>
<span>= 0.427 m </span>

<span>Use now the formula to get the boiling point.</span>

<span>delta Tb = Kbm </span>
<span>= (0.52)(0.427) </span>
<span>= 0.22C </span>
8 0
3 years ago
The burning of a sample of propane
r-ruslan [8.4K]

Answer:

70.0°C

Explanation:

We are given;

  • Amount of heat generated by propane as 104.6 kJ or 104600 Joules
  • Mass of water is 500 g
  • Initial temperature as 20.0 ° C

We are required to determine the final temperature of water;

Taking the initial temperature is x°C

We know that the specific heat of water is 4.18 J/g°C

Quantity of heat = Mass × specific heat × change in temperature

In this case;

Change in temp =(x-20)° C

Therefore;

104600 J = 500 g × 4.18 J/g°C × (x-20)

104600 J = 2090x -41800

146400 = 2090 x

  x = 70.0479

     =70.0 °C

Thus, the final temperature of water is 70.0°C

7 0
3 years ago
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