Answer:
60% decrease
Step-by-step explanation:
you would do 5-2=3 ,
5/3
and then multiply by 100
put in an positive number for x and check
2 - 5 = -3
5 - 2 = 3
- 2 + 5 = 3
5 + (-2) = 2
so the only different one is the first
'll use the binomial approach. We need to calculate the probabilities that 9, 10 or 11
<span>people have brown eyes. The probability that any one person has brown eyes is 0.8, </span>
<span>so the probability that they don't is 1 - 0.8 = 0.2. So the appropriate binomial terms are </span>
<span>(11 C 9)(0.8)^9*(0.2)^2 + (11 C 10)(0.8)^10*(0.2)^1 + (11 C 11)(0.8)^11*(0.2)^0 = </span>
<span>0.2953 + 0.2362 + 0.0859 = 0.6174, or about 61.7 %. Since this is over 50%, it </span>
<span>is more likely than not that 9 of 11 randomly chosen people have brown eyes, at </span>
<span>least in this region. </span>
<span>Note that (n C r) = n!/((n-r)!*r!). So (11 C 9) = 55, (11 C 10) = 11 and (11 C 0) = 1.</span>
Answer:
Step-by-step explanation:
Average rate equals the negative of delta concentration of reactants
Answer:
Price of 1 adult ticket is <u>$10.8</u> and Price of 1 children ticket is <u>$5.4</u>.
Step-by-step explanation:
Given:
Number of adults = 2
Number of Children = 6
Total Amount of tickets sold = $54.
We need to find the price of one children's ticket and one adult ticket.
Solution:
Let the Cost of 1 adult ticket be 'x'.
Now Given:
Children tickets are on sale,half price of adult tickets.
Cost of 1 Children ticket = 
Total Amount is equal to Number of adults multiplied by Cost of adult ticket plus Number of Children multiplied by Cost of Children ticket.
Framing in equation for we get;
Cost of 1 adult ticket = $10.8
Cost of 1 children ticket = 
Hence Price of 1 adult ticket is <u>$10.8</u> and Price of 1 children ticket is <u>$5.4</u>.
