Answer:
0.4546
Step-by-step explanation:
nCr = n!/(n-r)!r!
Number of ways of selecting the four defective voltage regulators from 12 = 12C4 = 12!/(12-4)!4! = 12!/8!4! = (12 *11*10*9)/(4*3*2*1)
12C4 = 495 ways
Number of ways of selecting 2 defectives from line 1 = 6C2 * 6C2
6C2 = 6!/(6-2)!2! = 6!/4!2! = (6*5)/(2*1) = 15
6C2 * 6C2 = 15*15 = 225 ways
Probability = Number of possible outcomes/ Number of total outcomes
Probability that exactly 2 of the defective regulators came from line 1 = 225/40.95 = 0.4546
The fraction form 4/7 and the decimal form is 0.571428
Answer: -8x^3y^2 (choice B)
The coefficients multiply to 4 times -2 = -8
the x terms multiply to x^2 times x = x^(2+1) = x^3
The y terms multiply to y times y = y^(1+1) = y^2
So that's how I ended up with -8x^3y^2
Answer is A.
You start by adding the 7 to the opposite side. Giving you 19. You divide both sides by -2 which gives you x on one side and -9.5 on the other.
-2x-7=12
-2x=12(+7)
-2x=19
x=19/-2
x=-9.5
Answer:
not -7 just 7
Step-by-step explanation:
