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Vikki [24]
3 years ago
6

Find the measure of angle 1

Mathematics
1 answer:
nikklg [1K]3 years ago
4 0

Answer:

Angle 1, 2, 4 = 45 degrees

Step-by-step explanation:

2x+15 = x+30

-15 both sides

2x = x+15

-x both sides

x = 15

Plug x = 15 into x+30 or 2x+15

15+30 = 45

2(15)+15 = 45

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Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z
kompoz [17]

a.

f_{X,Y,Z}(x,y,z)=\begin{cases}Ce^{-(0.5x+0.2y+0.1z)}&\text{for }x\ge0,y\ge0,z\ge0\\0&\text{otherwise}\end{cases}

is a proper joint density function if, over its support, f is non-negative and the integral of f is 1. The first condition is easily met as long as C\ge0. To meet the second condition, we require

\displaystyle\int_0^\infty\int_0^\infty\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=100C=1\implies \boxed{C=0.01}

b. Find the marginal joint density of X and Y by integrating the joint density with respect to z:

f_{X,Y}(x,y)=\displaystyle\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dz=0.01e^{-(0.5x+0.2y)}\int_0^\infty e^{-0.1z}\,\mathrm dz

\implies f_{X,Y}(x,y)=\begin{cases}0.1e^{-(0.5x+0.2y)}&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}

Then

\displaystyle P(X\le1.375,Y\le1.5)=\int_0^{1.5}\int_0^{1.375}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy

\approx\boxed{0.12886}

c. This probability can be found by simply integrating the joint density:

\displaystyle P(X\le1.375,Y\le1.5,Z\le1)=\int_0^1\int_0^{1.5}\int_0^{1.375}f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz

\approx\boxed{0.012262}

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3 years ago
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soldier1979 [14.2K]
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Please help ASAP! thank you ( geometry)
Lostsunrise [7]

Answer:

.

Step-by-step explanation:

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harina [27]
The center is at (0,0) so the equation will be like

x^2 + y^2 = r^2      where r = radius of the circle.

from the diagram you can see that r = 4

answer is x^2 + y^2 = 16
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the Circle fit in a square with a side of 12 inches what is the approximate area of the shaded region between the square in the
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that is the solution to the question

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