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Savatey [412]
3 years ago
12

La presidencia municipal va a construir una banqueta que pase por el centro del parque y tiene una circunferencia de 270m. Cuant

o medira esa banqueta
Mathematics
1 answer:
horsena [70]3 years ago
4 0

Answer:

You said: The municipal presidency is going to build a sidewalk that goes through the center of the park and has a circumference of 270m. How long will that bench measure? Your answer

Step-by-step explanation:

Area: r^r * 3.14

Circumference: 2r * 3.14

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What is the distance of the line?<br> Remember the distance formula is (23 - 23) + (42 -
vivado [14]

Answer:

<em>The distance of the line is 10.82</em>

Step-by-step explanation:

Distance Between two Points in the Plane

Given two points A(x1,y1) and B(x2,y2), the distance between them is:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The graph clearly shows the points (-5,4) (4,-2), thus the distance is:

d=\sqrt{(4-(-5))^2+(-2-4)^2}=\sqrt{9^2+(-6)^2}

d=\sqrt{81+36}=\sqrt{117}=10.82

The distance of the line is 10.82

4 0
3 years ago
Help with this plaese
WARRIOR [948]
So the rise over run is 5/-4
To start off take 10 degrees/96 cups
If you look at the pattern the degrees go up by 5 and the cups go down by 4

So I believe the answer should be
25 degrees = 84 cups
7 0
2 years ago
Read 2 more answers
Can someone please answer?
Lady_Fox [76]

Answer:

Volume = 803.84 cubic inches

Step-by-step explanation:

Volume = πr²h

= 3.14 x 8 x 8 x 4

= 3.14 x 256

= 803.84 cubic inches

7 0
2 years ago
I need some help with this math problem
gizmo_the_mogwai [7]

Step-by-step explanation:

15 long

12 wide

10 high

we need all for walls

hight times length two times ( these are the front and back walls )

hight times width two times ( These are the side walls )

the roof is

width times length (only once as only the ceiling)

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8 0
2 years ago
A sample of 25 undergraduates reported the following dollar amounts of entertainment expenses last year:
marin [14]

Answer:

Range = 85

\sigma = 28.71

Interval = [666.78, 781.62]

Step-by-step explanation:

Given

The data for 25 undergraduates

Solving (a): Range and Standard deviation

The range is:

Range = Highest - Least

From the dataset:

Highest = 772

Least = 687

So:

Range = Highest - Least

Range = 772-687

Range = 85

The standard deviation is:

\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n}}

First, calculate the mean

\bar x = \frac{769 +691 +............+715}{25}

\bar x = \frac{18105}{25}

\bar x = 724.2

So, the standard deviation is:

\sigma = \sqrt{\frac{(769-724.2)^2 +(691-724.2)^2 +(699-724.2)^2 +(730-724.2)^2 +............+(715-724.2)^2}{25}}

\sigma = \sqrt{\frac{20604}{25}}

\sigma = \sqrt{824.16}

\sigma = 28.71

Solving (b): The interval of the 95% of the observation.

Using the emperical rule, we have:

Interval = [\bar x - 2*\sigma, \bar x+ 2*\sigma]

Interval = [724.2 - 2*28.71, 724.2 + 2*28.71]

Interval = [666.78, 781.62]

4 0
3 years ago
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