Answer:
answer of this question is = m⁹n⁶p¹⁵
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I. Multiply the first function by the second one.
f(x)*g(x) = (x^2+3x-4)*(x+4) = x^3 + 3x^2 - 4x + 4x^2 + 12x -16 = x^3 +7x^2 + 8x - 16.
The domain of this new function is the set of all real numbers (R). Other notation: from minus infinity to plus infinity. We came to this conclusion because the new function poses no restrictions; regardless of which x-value you take, you will get the appropriate y-value.
II. f(x)/g(x) = (x^2+3x-4)/(x+4) =
Ask yourself: which two numbers add up to 3 and multiply to -4? It's -1 and 4. Now we can represent f(x) as (x-1)(x+4).
Since we're dividing these 2 brackets by g(x)=x+4, we may now cancel (x+4). All that's left is x-1.
The domain here is the same as in the previous task - it is R.
Answer:
a=4
Step-by-step explanation:
5a-8=8+a
4a-8=8
4a=16
a=4
480700. The different combinations of students that could go on the trip with a total of 25 student, but only 18 may go, is 480700.
The key to solve this problem is using the combination formula 
. This mean the number of ways to choose a sample of r elements from a set of n distinct objects where order does not matter and replacements are not allowed.
The total of students is n and the only that 18 students may go is r:
754,863 rounded to the nearest ten thousands is 750,000
