Answer: 5.37
Step-by-step explanation:
Let x = ACT scores.
Given: ACT scores have a mean of 20.8 and 9 percent of the scores are above 28. The scores have a distribution that is approximately normal.
i.e. P(X>28)=0.09 (i)
Now,
(ii)
One -tailed z value for p-value of 0.09 =1.3408 [By z-table]
From (i) and (ii)
Hence, the standard deviation = 5.37
Answer:
a) The expected value is given by:
and the variance is given by:
b)
And we can find this probability with the following Excel code:
=1-BINOM.DIST(25,50,0.4,TRUE)
And we got:
c) 1) Random sample (assumed)
2) np= 50*0.4= 20 >10
n(1-p) =50*0.6= 30>10
3) Independence (assumed)
Since the 3 conditions are satisfied we can use the normal approximation:
d)
e)
Step-by-step explanation:
Previous concepts
The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".
Let X the random variable of interest, on this case we now that:
The probability mass function for the Binomial distribution is given as:
Where (nCx) means combinatory and it's given by this formula:
Part a
The expected value is given by:
and the variance is given by:
Part b
For this case we want to find this probability:
And we can find this probability with the following Excel code:
=1-BINOM.DIST(25,50,0.4,TRUE)
And we got:
Part c
1) Random sample (assumed)
2) np= 50*0.4= 20 >10
n(1-p) =50*0.6= 30>10
3) Independence (assumed)
Since the 3 conditions are satisfied we can use the normal approximation:
Part d
We want this probability:
Part e
For this case we use the continuity correction and we have this:
Answer:
Step-by-step explanation:
Since the scale factor of 0.75 is less than 1, So the dilated image is a reduced image.
Thus the scale factor of 0.75 reduces the dilated image.
Hope this helped!
<h3>~AnonymousHelper1807</h3>