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dezoksy [38]
3 years ago
11

ft(1-m\right)=9-2m" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
Jobisdone [24]3 years ago
6 0

Answer:

your answer is m=15/8

Musya8 [376]3 years ago
4 0

Answer:

m=\frac{15}{8}

Step-by-step explanation:

-6\left(1-m\right)=9-2m

-6(1-m)=-6+6m

-6+6m=9-2m

<u>Add 6 to both sides:-</u>

<u />-6+6m+6=9-2m+6

6m=-2m+15

<u>Now, add 2m to both sides:-</u>

<u />6m+2m=-2m+15+2m

<u>Divide both sides by 8:-</u>

<u />\frac{8m}{8}=\frac{15}{8}

m=\frac{15}{8}

<u>-----------------------</u>

<u>OAmalOHopeO</u>

<u>-----------------------</u>

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By the same logic a 140 pound dog would have to eat twice what a 70 pound dog eats, that is 10 cups of dry dog food a day, so 7 1/2 cups are not enough.

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4 years ago
X^4 + 25 = 26x^2<br><br>please answer quick. I'll give brainliest rothe first person​
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{ \leadsto{ \sf{ \green{ {x}^{4}  + 25 = 26 {x}^{2} }}}} \\  \\ { \leadsto{ \sf{ \green{ {x}^{4}  - 26 {x}^{2}  + 25 = 0}}}} \\  \\ { \sf{ \underline{ \blue{let  \:  \: {x}^{2} \:  be \: equal \: to \: a}}}}

{ \leadsto { \green{ \sf{ {a}^{2}  - 26a + 25 = 0}}}} \\  \\ { \leadsto{ \green{ \sf{ {a}^{2}  - (a + 25a) + 25 = 0}}}} \\  \\ { \leadsto{ \green{ \sf{ {a}^{2}  - a - 25a + 25 = 0}}}} \\  \\ { \leadsto{ \green{ \sf{a(a - 1) - 25(a - 1) = 0}}}}

{ \leadsto{ \sf{ \green{(a - 1)(a - 25) = 0}}}} \\  \\ { \sf{ substituting \: value \: of \: a}} \\  \\ { \rightarrow{ \sf{ \blue{( {x}^{2}  - 1)( {x}^{2}  - 25) = 0}}}} \\  \\ { \sf {{x}^{2}  = 1}}  \\ { \sf{ \underline{x = \: ±  \: 1}}} \\  \\  \\ { \sf {x}^{2}  = 25}  \\ { \sf{ \underline{x =  \: ± \: 5}}}

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3 years ago
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3 years ago
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4 years ago
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Range of f(x)=-x+5 with domain of [-3,2] in the same notation as the domain.
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