Question

Need help asap algebra 2

Answer 1

Answer:

Hello,

Step-by-step explanation:

a)

$\Large h(x)=\sqrt[3]{x+2} \ -3\\\\h(x)=-3\\\Longrightarrow\ \sqrt[3]{x+2} \ -3=-3 \\\\\Longrightarrow\ \sqrt[3]{x+2} =0\\\\\Longrightarrow\ (\sqrt[3]{x+2}) ^3=0^3\\\\\Longrightarrow\ x+2=0\\\\\Longrightarrow\ x=-2$

b)

$-3=k(x)=h(x-1)+2=\sqrt[3]{(x-1)+2} -3=\large \sqrt[3]{x+1} -3\\\\\\\Longrightarrow\ \sqrt[3]{x+1}=0\\\\x+1=0\\\\x=-1$