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2 years ago

A car covers a distace of 20km in 20 seconds. Calculate its speed in km/h m/s.

Physics

1 answer:

BartSMP [9]2 years ago

6 0

Answer:

speed = 3600 kilometers per hour

= 3600 km/h

speed = 1000 meters per second

= 1000 m/s

Answer From Gauth Math

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Nostrana [21]

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A diver dives off of a raft - what happens to the diver? the raft? how does this relate to newton's third law? action force: ___

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3 years ago

Read 2 more answers

A) Charge q1 = +5.60 nC is on the x-axis at x = 0 and an unknown charge q2 is on the x-axis at x = -4.00 cm. The total electric

jeka94

Answer:

a) F₃₁ = 63.0 μN

b) F₃₂ = - 14.0 μN

c) q₂ = - 5.0 nC

Explanation:

Assuming that the three charges can be taken as point charges, the forces between them must obey Coulomb's Law, and can be found independent each other, applying the superposition principle.
So, we can find the force that q₁ exerts along the x-axis on q₃, as follows:

$F_{31} =\frac{k*q_{1}*q_{3} }{r_{13}^{2}} = \frac{9e9Nm2/C2*5.6e-9C*2.0e-9C}{(0.04m)^{2}} = 63.0 \mu N (1)$

Since total force exerted by q₁ and q₂ on q₃ is 49.0 μN, we can find the force exerted only by q₂ (which is along the x-axis only too) just by difference, as follows:

$F_{32} = F_{3} - F_{31} = 49.0\mu N - 63.0\mu N = -14.0 \mu N (2)$

Finally, in order to find the value of q₂, as we know the value and sign of F₃₂, we can apply again the Coulomb's Law, solving for q₂, as follows:

$q_{2} = \frac{F_{32} * r_{23}^{2} }{k*q_{3}} = \frac{(-14\mu N)*(0.08m)^{2}}{9e9Nm2/C2* 2 nC} = - 5 nC (3)$

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2 years ago

Pleaseeee help!!!! I will mark you as brainlinest for correct answer!!!!!!!

GrogVix [38]

I do believe that the answer is D.

Hope this is right! Have a great day! :-)

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2 years ago

A car covers a distace of 20km in 20 seconds. Calculate its speed in km/h m/s.​

A car covers a distace of 20km in 20 seconds. Calculate its speed in km/h m/s.