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3 years ago

Describe and give an example of a normal force

Physics

1 answer:

lozanna [386]3 years ago

6 0

Force is a push or pull

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Frank does 2400J of work in climbing a set of stairs. If he does the work in 6 seconds, what is his power output?

timurjin [86]

Power = Work Done / Time taken

Where Work Done is Joules, and Time is in Seconds, Power is in Watts

= 2400 J / 6 seconds

= 400 Watts

The power output is 400 Watts.

4 0

3 years ago

Does the tide that the moon raises on the earth different?

alukav5142 [94]

Answer:

No the gravity of the moon pulls the water making high tide

Explanation:

7 0

3 years ago

To win the game, a placekicker must kick a football from a point 44 m (48.1184 yd) from the goal, and the ball must clear the cr

Ganezh [65]

Answer:

The distance by the ball clear the crossbar is 1.15 m

Explanation:

Given that,

Distance = 44 m

Speed = 24 m/s

Angle = 31°

Height = 3.05 m

We need to calculate the horizontal velocity

Using formula of horizontal velocity

$u_{x}=u\cos\theta$

Put the value into the formula

$u_{x}=24\cos(31)$

$u_{x}=20.5\ m/s$

We need to calculate the vertical velocity

Using formula of vertical velocity

$u_{y}=u\sin\theta$

Put the value into the formula

$u_{y}=24\sin(31)$

$u_{y}=12.3\ m/s$

We need to calculate the time

Using formula of time

$t=\dfrac{d}{u_{x}}$

Put the value into the formula

$t=\dfrac{44}{20.5}$

$t=2.1\ sec$

We need to calculate the vertical height

Using equation of motion

$h=u_{y}t+\dfrac{1}{2}at^2$

Put the value into the formula

$h=12.3\times2.1-\dfrac{1}{2}\times9.8\times(2.1)^2$

$h=4.2\ m$

We need to calculate the distance by the ball clear the crossbar

Using formula for vertical distance

$d=h-3.05$

Put the value of h

$d=4.2-3.05$

$d=1.15\ m$

Hence, The distance by the ball clear the crossbar is 1.15 m

7 0

4 years ago

As you look out of your dorm window, a flower pot suddenly falls past. The pot is visible for a time t, and the vertical length

ololo11 [35]

Answer:

Explanation:

4 0

3 years ago

Calculate the potential energy of a 20-kg sled at 40 meters

irakobra [83]

Answer: 7840N

Explanation:

Given that

Potential energy = ?

Mass of sled = 20-kg

Distance = 40 meters

Acceleration due to gravity = 9.8m/s^2

Recall that potential energy is the energy possessed by a body at rest

i.e potential energy = mass m x acceleration due to gravity g x distance h

P.E = mgh

P.E = 20kg x 9.8m/s^2 x 40m

P.E = 7840N

Thus, the potential energy of the sled is 7840N

5 0

3 years ago

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