A man is dragging a trunk up the loading ramp of a mover's
1 answer:
Answer:
Horizontal component = 241 N
Vertical component = 287 N
Explanation:
Given:
Force = F = 375 N
Referring to diagram attached, the force F is making an angle
theta = 20+30 = 50 with the horizontal.
Horizontal component = F*cos(theta) = 375*0.64278 = 241 N
Vertical component = F*sin(theta) = 375*0.76604 = 287 N
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Answer:
The orbital speed of the electron is 2.296 x 10⁶ m/s
Explanation:
Given;
radius of the circular orbit, r = 5.041 × 10⁻¹¹ m
In the Bohr’s model of the hydrogen atom, the velocity of the electron is given as;
where;
h is Planck's constant
m is mass of electron
r is the radius of the circular orbit
n is the energy level of hydrogen in ground state
Substitute in these values and solve for V
Therefore, the orbital speed of the electron is 2.296 x 10⁶ m/s