A man is dragging a trunk up the loading ramp of a mover's
1 answer:
Answer:
Horizontal component = 241 N
Vertical component = 287 N
Explanation:
Given:
Force = F = 375 N
Referring to diagram attached, the force F is making an angle
theta = 20+30 = 50 with the horizontal.
Horizontal component = F*cos(theta) = 375*0.64278 = 241 N
Vertical component = F*sin(theta) = 375*0.76604 = 287 N
You might be interested in
Work done is given by product of force and displacement due to that force
So here we will have
here we know that
Now work done is given as
so it will do 16 J work to move the box