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SVEN [57.7K]
2 years ago
15

PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER PLS GIVE ME A STEP BY STEP EXPLANATION!!

Mathematics
2 answers:
Yuri [45]2 years ago
5 0

Answer:

Below

Step-by-step explanation:

Volume = area of the circular side * length

Radius of circle = 10

V  = pi r^2 l = pi *10^2 * 6

= 100 pi

= 1884 in^2

tia_tia [17]2 years ago
3 0
The answer would be c
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By using the second condition, we conclude that there are 23 white roses in the tray.

<h3>How many white roses are in the tray?</h3>

First, we know that there are a total of 50 roses in the tray, and we have the conditions:

  • <em>"There is at least 1 red rose among any 24 randomly selected roses"</em>
  • <em>"There is at least 1 white rose among any 28 randomly selected roses".</em>

The second statement means that, always that we take 28 roses, at least one of them is white. So, there are 27 roses in the tray that are not white.

Whit that in mind, if the 28th rose must be white, then all the remaining roses in the tray are white, this means that there are:

50 - 27 = 23 white roses.

If you want to learn more about counting.

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6 0
1 year ago
Mykel is picking out some movies to rent, and he has narrowed down his selections to 66 foreign films, 33 children's movies, 66
uranmaximum [27]

Answer:

Mykel can make 2.79 x 10³² different combinations

Step-by-step explanation:

We can solve this problem using combination

The formula for combination is ⁿCₐ = \frac{n!}{(n - a)!a!}

where n = total number of choices available

a = number of items being chosen

The total movies Mykel wants is 99.

Taking out the sure 66 drama movies,

Mykel is left with 99 - 66 choices = 33 choices.

The total number of choices he is left with is 66 foreign + 33 children + 44 documentaries = 143 movies

Hence, our n = 143 movies

and a = 33 choices

Hence we do, ¹⁴⁴C₃₃ = \frac{143!}{(143 - 33)!33!} = \frac{143!}{110!33!} 2.79 x 10³² combinations

∴ Mykel can make 2.79 x 10³² different combinations.

7 0
3 years ago
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<em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em>

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<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>1</em><em>2</em><em> </em><em>pie</em>

<em>So </em><em>the</em><em> </em><em>ans</em><em>wer</em><em> </em><em>is</em><em> </em><em>1</em><em>2</em><em> </em><em>pie.</em>

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ANEK [815]

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