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2 years ago

By completing the square, find the maximum or minimum point of the quadratic

Mathematics

1 answer:

xenn [34]2 years ago

4 0

Answer:

hello my lovely friendship

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Newborn males have weights with a mean of 3272.8 g and a standard deviation of 660.2 g. Newborn females have weights with a mean

Maksim231197 [3]

The correct option is: a female who weighs 1500 g

Explanation

Formula for finding the z-score is: $z= \frac{X-\mu}{\sigma}$

Newborn males have weights with a mean $(\mu)$ of 3272.8 g and a standard deviation $(\sigma)$ of 660.2 g.

So, the z-score for the newborn male who weighs 1500 g will be.......

$z(X=1500)=\frac{1500-3272.8}{660.2}=-2.685... \approx -2.69$

According to the normal distribution table, $P(z=-2.69)=0.0036 = 0.36\%$

Now, newborn females have weights with a mean $(\mu)$ of 3037.1 g and a standard deviation $(\sigma)$ of 706.3 g.

So, the z-score for the newborn female who weighs 1500 g will be.......

$z(X=1500)=\frac{1500-3037.1}{706.3}=-2.176... \approx -2.18$

According to the normal distribution table, $P(z=-2.18)=0.0146 = 1.46\%$

As we can see that the probability that a newborn female has weight of 1500 g is greater than newborn male, so a newborn female has the weight of 1500 g that is more extreme relative to the group from which he came.

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3 years ago

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Snezhnost [94]

Answer:

Step-by-step explanation:

Absolute Value is the distance from 0, so when you have -|22| that means its the absolute value of 22 then add the negative sign so that means it's further from 0 than |-22|.

I hope this will help.

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Creating and solving formulas for geometric series:mastery test

Levart [38]

Answer:

D. $y = 5\cdot \Sigma_{i=0}^{4} \left(\frac{1}{3} \right)^{i}$

Step-by-step explanation:

Let be $y = \Sigma_{i = 0}^{4} \left[5\cdot \left(\frac{1}{3} \right)^{i}\right]$ . To find the equivalent expression we must use the following property:

$y = c\cdot \Sigma_{i = 0}^{n} p(x) = \Sigma_{i=0}^{n} [c\cdot p(x)]$ (1)

Based on this fact, we find the following equivalence:

$y = 5\cdot \Sigma_{i=0}^{4} \left(\frac{1}{3} \right)^{i}$

Hence, the correct answer is D.

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Step-by-step explanation:

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