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larisa [96]
3 years ago
11

2(3+ ‐ 4)(7‐3)÷(2‐ ‐2)​

Mathematics
1 answer:
steposvetlana [31]3 years ago
4 0
The answer is 2 hopefully I answered your question in time
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Plz help me with number 8 plz help me I’m begging you plz help me I need your help plz help me I’m begging you plz help me
vampirchik [111]

Answer:

B. 990<s<1,850

6 0
3 years ago
Read 2 more answers
Mary can read 22 pages in 30 minutes how long would it take her to read a 100 page book? Right your answer in hours and minutes
mario62 [17]
30 divided by 22= 1.36 
1.36 minutes for each page, to check 1.36x22= 29.92
1.36x100=  136 minutes.
Mary would need about 2 hours and 16 minutes to read a 100 page book.
5 0
3 years ago
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Write the interval (5,100] as an inequality and using set notation
drek231 [11]

Answer: { x | 5 < x ≤ 100 }  OR  { x ∈ ℝ | 5 < x ≤ 100 }

Step-by-step explanation:

{ x | 5 < x ≤ 100 }

This means:

"The set of all x's, such that x is greater than 5 and less than or equal to 100"

Another acceptable way to write this is

{ x ∈ ℝ | 5 < x ≤ 100 }

"x ∈ ℝ" simply means x is an element of all real numbers

7 0
3 years ago
The accompanying summary data on total cholesterol level (mmol/l) was obtained from a sample of Asian postmenopausal women who w
dimulka [17.4K]

Answer:

99% CI:

-4.637\leq\mu_v-\mu_o\leq 3.737

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

s_{Md}=\sqrt{\frac{2MSE}{n_h}}

The MSE can be calculated as

MSE=\frac{(SSE_1+SSE_2)}{df} =\frac{(n_1s_1)^2+(n_2*s_2)^2}{n_1+n_2-2}\\\\MSE=\frac{(85*1.05)^2+(96*1.20)^2}{85+96-2}=\frac{7965.56+13272.04}{179} =118.65

The weighted sample size nh can be calculated as

n_h=\frac{2}{1/n_1+1/n_2}=\frac{2}{1/85+1/96}=\frac{2}{0.0222} =90.16

The standard deviation then becomes

s_{Md}=\sqrt{\frac{2MSE}{n_h}}=\sqrt{\frac{2*118.65}{90.16}}=\sqrt{2.632} =1.623

The z-value for a 99% confidence interval is z=2.58.

The difference between means is

\Delta M=M_v-M_o=5.10-5.55=-0.45

Then the confidence interval can be constructed as

\Delta M-z*s_{Md}\leq\mu_v-\mu_o\leq \Delta M+z*s_{Md}\\\\ -0.45-2.58*1.623\leq\mu_v-\mu_o\leq -0.450+2.58*1.623\\\\-0.450-4.187\leq\mu_v-\mu_o\leq-0.450+4.187\\\\-4.637\leq\mu_v-\mu_o\leq 3.737

8 0
3 years ago
H(t)=480t-16t^2<br><br> solve for t <br><br> PLEASE SHOW WORK
Andru [333]

Answer:

x = √30 or -√30

Step-by-step explanation:

480 - 16x^2 = 0

divide both sides by 16

30 - x^2 = 0

-x^2 + 30 = 0

-x^2 = -30

X^2 = 30

x = ± √30

x = √30 or -√30

7 0
3 years ago
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