Answer
given,
initial speed of hockey player= 0 m/s
mass of the helmet, m = 1.3 Kg
initial speed of the helmet, u = 0 m/s
final speed of the helmet, v = 6 m/s
recoil speed of the hockey player, v' = 0.25 m/s
we need to calculate the mass of the hockey player, M = ?
using conservation of momentum
m u + M u' = M v' + m v
initial speed of ice skater is zero
1.3 x 0 + M x 0 = M x (-0.25) + 1.3 x 6
negative sign is taken because recoil velocity is in opposite direction
0 = -0.25 M + 7.8
0.25 M = 7.8
M = 31.2 Kg
Hence, the mass of the young hockey player is equal to 31.2 Kg
Answer:
1 kg
Explanation:
The container has negligible mass and no heat is loss to the surrounding.
Mass of ice = 0.4kg, initial temperature of ice = -29oC, final temperature of the mixture = 26oC, mass of water (m2) = ?kg, initial temperature of water = 80oC, c ( specific heat capacity of water ) = 4200J/kg.K, Lf = heat of fusion of water = 3.36 × 10^5 J/kg
Using the formula:
Quantity of heat gain by ice = Quantity of heat loss by water
Quantity of heat gain by ice = mass of ice × heat of fusion of ice + mass of water × specific heat capacity of water = (0.4 × 3.36 × 10^ 5) + (0.4 × 4200 × (26- (-29) = 13.44 × 10^4 + 9.24 × 10^ 4 = 22.68 × 10^4 J
Quantity of heat loss by water = m2cΔT
Quantity of heat loss by water = m2 ×4200× (80 - 26) = m(226800)
since heat gain = heat loss
22.68 × 10^4 = 226800 m2
divide both side by 226800
226800 / 226800 = m2
m2 = 1 kg
Explanation:


<h3>BEFORE COLLISION)
<em> </em><em><u>INITI</u></em><em><u>AL</u></em><em><u> </u></em><em><u>MOM</u></em><em><u>. </u></em><em><u>OF</u></em><em><u> </u></em><em><u>BODY</u></em><em><u> </u></em><em><u>A</u></em><em><u> </u></em><em><u> </u></em></h3>
<em><u>PiA</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>m1u1</u></em>
<em><u>After</u></em><em><u> </u></em><em><u>collis</u></em><em><u>ion</u></em><em><u>)</u></em><em><u> </u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>. </u></em><em><u>B</u></em><em><u> </u></em><em><u> </u></em><em><u>I. </u></em><em><u>e</u></em><em><u> </u></em><em><u>piB</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>m2u2</u></em>
<h2>
<em><u>FINÅL</u></em><em><u> </u></em><em><u>MOMEN</u></em><em><u>TUM</u></em><em><u> </u></em><em><u>OF</u></em><em><u> </u></em><em><u>BØDY</u></em><em><u> </u></em><em><u>A</u></em><em><u> </u></em><em><u>I. </u></em><em><u>e</u></em><em><u> </u></em><em><u>PfA</u></em><em><u>=</u></em><em><u> </u></em><em><u>m1v1</u></em></h2>
<em><u>FINAL</u></em><em><u> </u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>. </u></em><em><u>B</u></em><em><u> </u></em><em><u>I. </u></em><em><u>e</u></em><em><u> </u></em><em><u>PfB</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>m2v2</u></em>
<em><u>ùr</u></em><em><u> ãñswer</u></em><em><u> </u></em><em><u>✌️</u></em>
♠️♠️♠️♠️♠️♠️
Correct answer choice is :
B) They are also called longitudinal waves.
Explanation:
S-waves, secondary waves, or shear waves are a kind of flexible wave also are one of the two principal kinds of elastic body waves, so called because they travel through the body of an object, unlike surface waves. It pushes and pulls the rock it travels through just like sound waves push and pull the air. The second kind of body wave is the S wave or secondary wave, which is the next wave you feel in an earthquake. An S wave is delayed than a P wave and can only move through solid rock, not through any fluid medium.
Answer:
False..
Explanation:
An electoMagnets attract iron due to the influence of their magnetic field upon the iron. ...