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jenyasd209 [6]
2 years ago
11

How many moles are there in 3.612 x 1024 molecules of CaO?

Chemistry
1 answer:
melamori03 [73]2 years ago
3 0

The number of moles in  3.612 x 10²⁴ molecules of CaO is  6 moles.

<h3>Number of moles in the molecules</h3>

The number of moles in  3.612 x 10²⁴ molecules of CaO is calculated as follows;

6.02 x 10²³ molecules = 1 mole

3.612 x 10²⁴ molecules = ?

= (3.612 x 10²⁴ ) / (6.02 x 10²³ )

= 6 moles

Thus, the number of moles in  3.612 x 10²⁴ molecules of CaO is  6 moles.

Learn more about number of moles here: brainly.com/question/15356425

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What geometric shape is the carbon dioxide molecule? The Lewis structure for CO2 contains two double bonds.
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Hydrocyanic acid, HCN, is a weak acid. (a) Write the chemical equation for the dissociation of HCN in water. (b) Identify the Br
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Answer: a) HCN(aq.)+H_2O\rightleftharoons H_3O^+(aq.)+CN^-(aq.)

b) HCN : acid CN^- :conjugate base.

And, H_2O : base H_3O^+: conjugate acid.

c) HCN(aq.)+NaOH(aq)\rightleftharoons NaCN(aq.)+H_2O(l)

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e) NaCN(aq)+HCl(aq)\rightarrow NaCl(aq.)+HCN(aq)

Explanation:

a) Weak acid is defined as the acid which does not completely dissociates when dissolved in water. They have high pH. These releases H^+ ions in their aqueous states.

The equation for the dissociation of HCN acid is given by:

HCN(aq.)+H_2O\rightleftharoons H_3O^+(aq.)+CN^-(aq.)

b) According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

For the given chemical equation:

HCN is loosing a proton, thus it is considered as an acid and after losing a proton, it forms CN^- which is a conjugate base.

And, H_2O is gaining a proton, thus it is considered as a base and after gaining a proton, it forms H_3O^+ which is a conjugate acid.

c) Neutralization reaction is a reaction in which an acid reacts with base to produce salt and water.

HCN(aq.)+NaOH(aq)\rightarrow NaCN(aq.)+H_2O(l)

d) The chemical equation for dissociation of NaCN in water.

NaCN(aq)\rightarrow Na^+(aq.)+CN^-(aq)

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