T(1/2)=1/(k[NO2])
[NO2]=1/(kt(1/2))
[NO2]=1/(0.54M-1 s-1*22s) seconds cancel
[NO2]=1/11.88=0.0842
inital mole= 0.0842*volume(2.5)=0.210 mols
Answer:
Option A, C, D
Explanation:
A reversible adiabatic process is an isentropic process as entropy remains constant. Thus,
Entropy change (Delta S) = integral of (Q_rev)/T
Thus, option A and C are correct
For a reversible process, entropy generation is a positive quantity or zero. hence, statement B is not true
In an Adiabatic processes, entropy do not decrease. Hence, option D is also correct
Answer:
Answer: What can experiments in a lab tell us about substances on Titan? Experiments in a lab can tell us that the lake did not evaporate in 2007 because the molecular attraction was a lot stronger, then it got weaker overtime.
How does Dr. Hayes' and Dr. Malaska’s research differ? Why are both research projects important? Their research differs because they were both talking about different things, Hayes was talking about how many lakes there were, while Malaska's was doing more hands on stuff like experiments. Both are important because we need to learn how the lakes formed, but we also need to do hands on experiments.
Explanation:
