From the formula of methane it is clear that one mole of methane has 4hydrogen atoms. So, 37.6×1023 hydrogen atoms are there in 25.0 g of methane. Therefore, 9.4×1023methane molecules and 9.4×1023 hydrogen and 37.6×1023carbon atoms are there in 25.0 g of methane.
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Answer:
47.1 L.
Explanation:
- To solve these problems, we can use the general law of ideal gas: <em>PV = nRT.</em>
where, P is the pressure of the gas in atm (P = 234.0 kPa/101.325 ≅ 2.31 atm) .
V is the volume of the gas in L (V = ??? L).
n is the no. of moles of the gas in mol (n = 3.9 mol).
R is the general gas constant (R = 0.082 L.atm/mol.K),
T is the temperature of the gas in K (T = 67.0 °C + 273.15 = 340.15 K).
The volume of the gas = nRT/P.
<em>∴ V = nRT/P </em>= (3.9 mol)(0.082 L.atm/mol.K)(340.15 K)/(2.31 atm) = <em>47.1 L.</em>
Answer:
It's true
Explanation:
Because in a physical change no now substance is formed And in this picture no new substance is formed.
I hope that helps you
Answer:
Calculated density = 0.8555g/ mL
Probable identity = Toulene
Explanation:
First off, the substance choices are;
isopropyl alcohol (density 0. 785 g/ mL)
toluene ( density 0.866g/ mL)
So upon calculation, if the density of the liquid substance is equal to either of the substances in the choice, it is that substance.
The relationship between density, mass and volume is given as;
Density = Mass / Volume
Mass = 38.5g
Volume = 45ml
Density = 38.5 / 45 = 0.8555g/ mL
Calculated density = 0.8555g/ mL
Among both substances, it is closest to toluene ( density 0.866g/ mL).
Probable identity = Toulene