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zaharov [31]
3 years ago
8

Explain why materials with metallic lattice structures can be used to make wires and connections that conduct electricity in ele

ctrical circuits.
Chemistry
1 answer:
kogti [31]3 years ago
7 0
<span>All metals have similar properties BUT, there can be wide variations in melting point, boiling point, density, electrical conductivity and physical strength.<span>To explain the physical properties of metals like iron or sodium we need a more sophisticated picture than a simple particle model of atoms all lined up in close packed rows and layers, though this picture is correctly described as another example of a giant lattice held together by metallic bonding.</span><span>A giant metallic lattice – the <span>crystal lattice of metals consists of ions (NOT atoms) </span>surrounded by a 'sea of electrons' that form the giant lattice (2D diagram above right).</span><span>The outer electrons (–) from the original metal atoms are free to move around between the positive metal ions formed (+).</span><span>These 'free' or 'delocalised' electrons from the outer shell of the metal atoms are the 'electronic glue' holding the particles together.</span><span>There is a strong electrical force of attraction between these <span>free electrons </span>(mobile electrons or 'sea' of delocalised electrons)<span> (–)</span> and the 'immobile' positive metal ions (+) that form the giant lattice and this is the metallic bond. The attractive force acts in all directions.</span><span>Metallic bonding is not directional like covalent bonding, it is like ionic bonding in the sense that the force of attraction between the positive metal ions and the mobile electrons acts in every direction about the fixed (immobile) metal ions of the metal crystal lattice, but in ionic lattices none of the ions are mobile. a big difference between a metal bond and an ionic bond.</span><span>Metals can become weakened when repeatedly stressed and strained.<span><span>This can lead to faults developing in the metal structure called 'metal fatigue' or 'stress fractures'.</span><span>If the metal fatigue is significant it can lead to the collapse of a metal structure.</span></span></span></span>
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An excess of oxygen reacts with 451.4 g of lead, forming 374.7 g of lead(II) oxide. Calculate the percent yield of the reaction.
Stels [109]

Answer: The percent yield of the reaction is 77.0 %

Explanation:

2Pb+O_2\rightarrow 2PbO

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

\text{Number of moles of lead}=\frac{451.4g}{207.2g/mol}=2.18moles

\text{Number of moles of lead oxide}=\frac{374.7g}{223.2g/mol}=1.68moles

According to stoichiometry:

2 moles of Pb produces = 2 moles of PbO_2

2.18 moles of Pb is produced by=\frac{2}{2}\times 2.18=2.18moles of PbO_2

Mass of PbO_2 =moles\times {\text {Molar mass}}=2.18\times 223.2g/mol=486.6

percent yield =\frac{374.7g}{486.6g}\times 100=77.0\%

3 0
3 years ago
Give the name and formula of the compound formed from the following elements: a) Sodium and nitrogen b) Oxygen and strontium c)
elena-s [515]

Answer:  a) Sodium and nitrogen : NaN_3  : sodium nitride.

b) Oxygen and strontium : SrO :  strontium oxide.

c) Aluminum and chlorine : AlCl_3  : aluminium chloride.

d) Cesium and bromine : CsBr  : cesium bromide.

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

a) Sodium and nitrogen : Here sodium is having an oxidation state of +1 called as Na^{+} cation and nitrogen forms an anion N^{3-} with oxidation state of -3. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral NaN_3  named as sodium nitride.

b) Oxygen and strontium : Here strontium is having an oxidation state of +2 called as Sr^{+} cation and oxygen forms an anion O^{2-} with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral SrO  named as strontium oxide.

c) Aluminum and chlorine : Here aluminium is having an oxidation state of +3 called as Al^{3+} cation and chlorine forms an anion Cl^{-} with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral AlCl_3  named as aluminium chloride.

d) Cesium and bromine : Here cesium is having an oxidation state of +1 called as Cs^{+} cation and bromine forms an anion Br^{-} with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral CsBr  named as cesium bromide.

7 0
3 years ago
Help me pls I put 49 point( every single point that I have) pls help me
Aliun [14]

Answer:

Chemical reaction, compound, molecule, covalent bonds, ionic bonds, ions. (first page)

Oxygen and hydrogen, 1 hydrogen 2 oxygen, H2O, a covalent bond, then mark off is always a liquid. (Second page)

Explanation:

6 0
3 years ago
According to the data to the right, which metal will change temperature the least if 50 J of heat is added? a) Iron b) Copper c)
AlladinOne [14]
The answer to your question is answer (D)
4 0
3 years ago
Calculate the mole fraction of the total ions in an aqueous solution prepared by dissolving 0.400 moles of MgBr2 in 850.0 g of w
diamong [38]
 <span>moles water = 850.0 g / 18.02 g/mol=47.2 
moles Mg2+ = 0.400 
moles Cl- = 2 x 0.400 = 0.800 
moles ions = 0.400 + 0.800= 1.2 
mole fraction ions = 1.2 / 1.2 + 47.2 =0.0248</span>
7 0
3 years ago
Read 2 more answers
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