Answer:
when I find out the two others ill edit this,sorry i'm kinda slow lol
Step-by-step explanation:
<u>Team Wins Losses</u>
Tigers 20
Vikings 25 10
Cougars 30 12
Pirates 35
<u>Answer:</u>
The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744
<u>Solution:</u>
Total number of coils = number of good coils + defective coils = 88 + 12 = 100
p(getting two good coils for two selection) = p( getting 2 good coils for first selection )
p(getting 2 good coils for second selection)
p(first selection) = p(second selection) = 
Hence, p(getting 2 good coil for two selection) = 
1/9 because i you plug in two of the points into y2 -y1 over x2 -x1 thats what you get.
A and B are points on j.
C and D are points on k.
Join AD and BC.
ABCD is a quadrilateral.
Clearly, the quadrilateral ABCD is the only plane that contains the points A, B, C and D.
Hence, correct answer is option A. Exactly one.
Here we have a system of equation like this:

from the first equation we get:

Substitute in the second equation we get:

Substitute i the first equation again we get:

We deduce that:

A is bigger than B.