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Contact [7]
2 years ago
9

Two observers are 300 ft apart on opposite sides of a flagpole. The angles of

Mathematics
1 answer:
Nezavi [6.7K]2 years ago
3 0
I know similar questions and have answers. do you want
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PLEASE HELP ME WITH THIS PROBLEM! PLEASE
Vladimir [108]

Answer:

when I find out the two others ill edit this,sorry i'm kinda slow lol

Step-by-step explanation:

<u>Team     Wins    Losses</u>

Tigers     20        

Vikings    25        10

Cougars   30       12

Pirates      35

4 0
3 years ago
A batch consists of 12 defective coils and 88 good ones. Find the probability of getting two good coils when two coils are rando
Allushta [10]

<u>Answer:</u>

The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744  

<u>Solution:</u>

Total number of coils = number of good coils + defective coils = 88 + 12 = 100

p(getting two good coils for two selection) = p( getting 2 good coils for first selection ) \times p(getting 2 good coils for second selection)

p(first selection) = p(second selection) = \frac{\text { number of good coils }}{\text { total number of coils }}

Hence, p(getting 2 good coil for two selection) = \frac{88}{100} \times \frac{88}{100} =\bold{0.7744}

5 0
3 years ago
find the slope of the line that contains the following points A : [ 17 , -12 ] and [ 17 , 8 ] and B [ 6 , -2 ] and [ -3 , 1 ]
Svetradugi [14.3K]
1/9 because i you plug in two of the points into y2 -y1 over x2 -x1 thats what you get.
4 0
3 years ago
If j and k are parallel lines, A and B are points on j, and C and D are points on k, how many planes contain points A, B, C, and
natita [175]

A and B are points on j.

C and D are points on k.

Join AD and BC.

ABCD is a quadrilateral.

Clearly, the quadrilateral ABCD is the only plane that contains the points A, B, C and D.

Hence, correct answer is option A. Exactly one.

8 0
3 years ago
A child bus ticket costs $0.40 and an adult’s ticket costs $0.70. A group of 11 individuals pays $5.90 for their fare.
oee [108]
Here we have a system of equation like this:
A+B=11\\&#10;0.4A+0.7B=5.9
from the first equation we get:
A=11-B
Substitute in the second equation we get:
0.4(11-B)+0.7B=5.9\\4.4-0.4B+0.7B=5.9\\0.3B=1.5\\B= \frac{1.5}{0.3}=5
Substitute i the first equation again we get:
A=11-B=11-5=6
We deduce that:
A > B A is bigger than B.
5 0
3 years ago
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