2. Give technical terms for

The function below takes a single parameter number_list which is a list that can contain integers and floats. Complete the funct

Andreas93 [3]

Answer:

def getLargest(number_list):
new_list = []
for x in number_list:
if(isinstance(x, int)):
new_list.append(x)
largest = max(new_list)
return largest

Explanation:

Firstly, create a function <em>getLargest()</em> that take one input parameter, <em>number_list</em>.

The function will filter out the float type number from the list by using <em>isinstance() </em>method (Line 5). This method will check if a current x value is an integer. If so, the x value will be added to <em>new_list</em>.

Next, use Python built-in <em>max</em> function to get the largest integer from the <em>new_list </em>and return it as output.

6 0

3 years ago

A CPU scheduler that assigns higher priority to the I/O-bound processes than the CPU-bound processes causes:

Sholpan [36]

Answer:

Low CPU utilization and high I/O utilization

Explanation:

6 0

1 year ago

Write code to take a String input from the user, then print the first and last letters of the string on one line. Sample run: En

Ainat [17]

<h2>Answer:</h2>

//import the Scanner class to allow for user input

import java.util.Scanner;

//Begin class definition

public class FirstAndLast{

//Begin the main method

public static void main(String []args){

//****create an object of the Scanner class.

//Call the object 'input' to receive user's input

//from the console.

Scanner input = new Scanner(System.in);

//****create a prompt to tell the user what to do.

System.out.println("Enter the string");

//****receive the user's input

//And store it in a String variable called 'str'

String str = input.next();

//****get and print the first character.

//substring(0, 1) - means get all the characters starting

//from the lower bound (index 0) up to, but not including the upper

//bound(index 1).

//That technically means the first character.

System.out.print(str.substring(0,1));

//****get and print the last character

//1. str.length() will return the number of character in the string 'str'.

//This is also the length of the string

//2. substring(str.length() - 1) - means get all the characters starting

// from index that is one less than the length of the string to the last

// index (since an upper bound is not specified).

// This technically means the last character.

System.out.print(str.substring(str.length()-1));

} // end of main method

} //end of class definition

<h2>Explanation:</h2>

The code has been written in Java and it contains comments explaining important parts of the code. Kindly go through the comments.

The source code and a sample output have also been attached to this response.

To run this program, copy the code in the source code inside a Java IDE or editor and save it as FirstAndLast.java

Download java

3 0

2 years ago

The ArrayList class contains a trim method that resizes the internal array to exactly the capacity. The trim method is intended

andreev551 [17]

Answer:

public void trimToSize() {

modCount++;

if (size < elementData.length) {

elementData = (size == 0)

? EMPTY_ELEMENTDATA

: Arrays.copyOf(elementData, size);

}

Now, the running time for copyOf() function is O(N) where N is the size/capacity of the ArrayList. Hence, the time complexity of trimToSize() function is O(N).

Hence, the running time of building an N-item ArrayList is O(N^2).

Please find the sample code below.

CODE

==================

import java.util.ArrayList;

public class Driver {

public static void main(String[] args) throws Exception{

int N = 100000;

ArrayList<Integer> arr = new ArrayList<>(N);

long startTime = System.currentTimeMillis();

for(int i=0; i<N; i++) {

arr.add(i);

arr.trimToSize();

}

long endTime = System.currentTimeMillis();

double time = (endTime - startTime)/1000;

System.out.println("Total time taken = " + time + " seconds.");

}

Explanation:

5 0

3 years ago

Design and implement an algorithm that gets as input a list of k integer values N1, N2,..., Nk as well as a special value SUM. Y

satela [25.4K]

Answer:

Follows are the code to this question:

def FindPair(Values,SUM):#defining a method FindPair

found=False;#defining a boolean variable found

for i in Values:#defining loop for check Value

for j in Values:#defining loop for check Value

if (i+j ==SUM):#defining if block that check i+j=sum

found=True;#assign value True in boolean variable

x=i;#defining a variable x that holds i value

y=j;#defining a variable x that holds j value

break;#use break keyword

if(found==True):#defining if block that checks found equal to True

print("(",x,",",y,")");#print value

else:#defining else block

print("Sorry there is no such pair of values.");#print message

Values=[3,8,13,2,17,18,10];#defining a list and assign Values

SUM=20;#defining SUM variable

FindPair(Values,SUM);#calling a method FindPair

Output:

please find the attachment:

Explanation:

In the above python code a method, "FindPair" is defined, which accepts a "list and SUM" variable in its parameter, inside the method "found" a boolean variable is defined, that holds a value "false".

Inside the method, two for loop is defined, that holds list element value, and in if block, it checks its added value is equal to the SUM. If the condition is true, it changes the boolean variable value and defines the "x,y" variable, that holds its value.
In the next if the block, it checks the boolean variable value, if the condition is true, it will print the "x,y" value, otherwise, it will print a message.

6 0

3 years ago