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Mice21 [21]
2 years ago
14

How to do this 74^{2n + 1}

Mathematics
1 answer:
nordsb [41]2 years ago
7 0

148ln(74)×74 2n

hop it help

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Explain how to solve a division problem with an divisor?
Tpy6a [65]
Multiply or divide the starting elements of a division problem (Divided and Divisor) by the same number, the quotient doesn't change. In other words, the answer is the same, and the remainder is multiplied or divided by that same number.

4 0
2 years ago
Find the volume of the cube. *<br> Answer choices: 30 1/2, 33 3/4, 31 1/4, 32 1/3
steposvetlana [31]

Answer:

volume = wide x length x deep

            = 3{1/3} ft x 2{1/2} ft x 3{3/4}ft

             = 10/3ft  x 5/2ft    x 15/4ft

             = (10 x 5 x 15)/(3 x 2 x 4) ft^3

              = 125/4 ft^3

               = 31{1/4} ft^3

Step-by-step explanation:

5 0
2 years ago
A number increased by 5 then divided by 2
alex41 [277]

Answer:

(x + 5) /2

Step-by-step explanation:

"a number" (this will represent as "x")

"increased" another way to say add or "+"

then divided by 2

If you wrote it out like this "x+5/2"it would be wrong because of PEMDAS making you want to divide first instead of after.

4 0
2 years ago
For the functions f(x) = 6x – 1 and g(x) = 4x2 + x, find (gºf)(x).<br> Provide your answer bolow
emmainna [20.7K]

For this case we have the following functions:

f (x) = 6x-1\\g (x) = 4x ^ 2 + x

We must find (g_ {o} f) (x):

By definition of composition of functions we have to:

(g_ {o} f) (x) = g (f (x))

So:

(g_ {o} f) (x) = 4 (6x-1) ^ 2 + (6x-1) = 4 ((6x) ^ 2-2 (6x) (1) + (1) ^ 2) + 6x -1 = 4 (36x ^ 2-12x + 1) + 6x-1 = 144x ^ 2-48x + 4 + 6x-1 = 144x ^ 2-42x + 3

We have different signs subtracted and the sign of the major is placed.

Finally we have to:

(g_ {o} f) (x) = 144x ^ 2-42x + 3

ANswer:

(g_ {o} f) (x) = 144x ^ 2-42x + 3

6 0
3 years ago
Write the expression as either the sine, cosine, or tangent of a single angle. (2 points)
sattari [20]

Answer:

cos(π/3)cos(π/5) + sin(π/3)sin(π/5) = cos(2π/15)

Step-by-step explanation:

We will make use of trig identities to solve this. Here are some common trig identities.

Cos (A + B) = cosAcosB – sinAsinB

Cos (A – B) = cosAcosB + sinAsinB

Sin (A + B) = sinAcosB + sinBcosA

Sin (A – B) = sinAcosB – sinBcosA

Given cos(π/3)cos(π/5) + sin(π/3)sin(π/5) if we let A = π/3 and B = π/5, it reduces to

cosAcosB + sinAsinB and we know that

cosAcosB + sinAsinB = cos(A – B). Therefore,

cos(π/3)cos(π/5) + sin(π/3)sin(π/5) = cos(π/3 – π/5) = cos(2π/15)

8 0
3 years ago
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