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Nana76 [90]
3 years ago
11

Francisco Typed a 36-word paragraph in minute. What is his typing speed, in words per minute?

Mathematics
1 answer:
olga_2 [115]3 years ago
5 0

Answer:36

Step-by-step explanation:

It says he typed 36 words in a paragraph in a minute which means he types 36 per minute

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T is directly proportional to the cube of r. T=21.76 when r=4 Find a formula for T in terms of r
maria [59]

Answer:

T = 0.34r³

Step-by-step explanation:

Given that T is directly proportional to r³ then the equation relating them is

T = kr³ ← k is the constant of variation

To find k use the condition T = 21.76 when r = 4 , then

21.76 = k × 4³ = 64k ( divide both sides by 64 )

0.34 = k

T= 0.34r³ ← equation of variation

3 0
3 years ago
Timmy takes out a loan for $750 for 15 months, but only receives $725 into his bank account. What is the simple interest rate ad
12345 [234]

Answer:

<u>The annual interest rate advertised by the bank is 2.67%  or 0.22% per month.</u>

Step-by-step explanation:

Let's evaluate the information given:

Amount of the loan = US$ 750

Duration of the loan = 15 months

Net amount received by Timmy into his bank account = US$ 725

Interests for the loan = Amount of the loan - Net amount received into bank account

Interests for the loan = 750 - 725

Interests for the loan = US$ 25

Now for calculating the interest rate, we do this operation:

Interest rate = Interests for the loan / Amount of the loan

Interest rate = 25/750 = 1/30 = 0.033 * 100 = 3.3%

But let's remember that this is for the total duration of the loan, 15 months. For calculating the annual interest rate, we do the following operation:

Annual interest rate = Loan interest rate/15 * 12 (We use 12 because the year has 12 months)

Annual interest rate = (1/30) /15 * 12

Annual interest rate = (1/30) * 1/15 * 12 = 1/450 * 12 = 12/450 = 4/150 = 2/75 = 0.0267 * 100 = 2.67% (Rounding to two decimals)

<u>The annual interest rate advertised by the bank is 2.67%  or 0.22% per month.</u>

5 0
4 years ago
Read 2 more answers
There are 150 students in the sixth grade at Nimitz Middle School. Of these students, 12 students write left-handed. What percen
AlladinOne [14]

Answer:

nnnnnnnnnnnnnnnnnnnnnn

Step-by-step explanation:

jjjjjjjjjjjjjjjjjjjjjjjj

8 0
3 years ago
What is the slope of the line?
miskamm [114]

Answer:

zero slope

Step-by-step explanation:

5 0
3 years ago
Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the
ziro4ka [17]

Answer:

a) \frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}

363.90 \leq \sigma^2 \leq 4430.80

Now we just take square root on both sides of the interval and we got:

19.08 \leq \sigma \leq 66.56

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

On this case we need to find the sample standard deviation with the following formula:

s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}&#10;And in order to find the sample mean we just need to use this formula:&#10;[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}

The sample deviation for this case is s=30.23

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=9-1=8

The Confidence interval is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and the critical values are:

\chi^2_{\alpha/2}=20.09

\chi^2_{1- \alpha/2}=1.65

And replacing into the formula for the interval we got:

\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}

363.90 \leq \sigma^2 \leq 4430.80

Now we just take square root on both sides of the interval and we got:

19.08 \leq \sigma \leq 66.56

Part b

For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

4 0
4 years ago
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