Question

PLS HELP!!what is the value of x?log2(x+7) = 2​

Answer 1

Answer:

-3

Step-by-step explanation:

log2(x+7) = 2​

Raise each side by base 2

2^log2(x+7) = 2^2​

x+7 = 4

Subtract 7 from each side

x+7-7 = 4-7

x=-3

Answer 2

Answer:  Choice A)  -3

Work Shown:

$\log_{2}(x+7) = 2\\\\x+7 = 2^2\\\\x+7 = 4\\\\x = 4-7\\\\x = -3$

Which leads us to choice A. In the second step, I used the rule that $\log_b(y) = x$ is equivalent to $y = b^x$. For each equation, the b is the base. Note how logs undo exponents and vice versa.