Answer:
The answer to your question is y = 2x + 11
Step-by-step explanation:
Data
Original line y = -(1/2)x + 5
Point (-4, 3)
Process
1.- Get the slope of the new line
- Slope of the original line = -1/2
If the lines are perpendicular, the slopes must be reciprocal
-1/2 reciprocal = 2
2.- Get the equation of the new line
y - y1 = m(x - x1)
y - 3 = 2(x + 4)
- Simplification
y - 3 = 2x + 8
- Solve for y
y = 2x + 8 + 3
y = 2x + 11
Without any more information we can't find the actual numerical representation of the length and width but we can give an expression that will allow us to find them...
We let the width equal x, so the length is 3x. That would be the dimensions...
length = 3x
width = x
So to find perimeter the expression would be
2(3x) + 2(x) =
6x + 2x =
8x
For the area it would be
a= length × width
a = 3x × x
a = 3x^2
-3s=-24 to find s you will divide both sides by -3
S=8
Answer:
y=4
Step-by-step explanation:The answer is y=4 because the line has no slope so it will not increase or decrease at a constant rate. If we were to plug it in it would be y=0/0+4. this basically means that the y-axis is equivalent to 0/0 (no slope) plus 4, we can then cancel out 0 since it is nothing simplifying the equation to y=4.
If all things can be made at the same time, then it would look something like this(all numbers should be rounded down):
127 of Prep: Wreath:127/3 = 42 prepped
127 of Prep: Tree:127/14 = 9 prepped
127 of Prep: Sleigh:127/4 = 31 prepped
104 of Painting: Wreath:104/2 = 52 painted(but because only 42 were prepped, your number will be 42 still)
104 of Painting: Tree:104/3 = 34 painted(As stated above, but with only 9)
104 of Painting: Sleigh:104/17 = 6 painted(this number will overwrite the number of prepped sleighs as only 9 could be painted in the allotted time.)
133 of Firing: Wreath:133/9 = 14 ready to go
133 of Firing: Tree:133/4 = 33(but only nine were painted so the number ready to go is 9)
133 of Firing: Sleigh:133/7 = 19(but only 6 are ready to go)
Final Results: Wreath - 14
Tree - 9
Sleigh - 6
