3 years ago

What is the length of each leg of the triangle below?

Mathematics

1 answer:

iragen [17]3 years ago

3 0

Answer:

option A

Step-by-step explanation:

since the given triangle is an isosceles triangle it's two remaining sides are equal

let the length of missing side be x

using pythagoras theorem

a^2 + b^2 = c^2

x^2 + x^2 = 22^2

2x^2 = 484

x^2 = 484/2

x = $\sqrt{242}$

x = $11\sqrt{2}$

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The measure of angle A is 4 degrees greater than the measure of angle B. The two angles are complementary. Find the measure for

svetlana [45]

Given:
Angle A is 4 degrees greater than the measure of Angle B. Both angles are complementary

Complementary angles have a sum of 90°

Angle A = x + 4° ; Angle B = x

x + 4° + x = 90°
2x = 90° - 4°
2x = 86°
x = 86° ÷ 2
x = 43° ANGLE B.

Angle A = x + 4° ⇒ 43° + 4 = 47°

Given:
Angle D is 5 times the measure of Angle E. These angles are supplementary. This means that their sum is 180°

Angle D = 5x ; Angle E = x

5x + x = 180°
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x = 30° Angle E.

Angle D = 5x = 5(30) = 150°

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3 years ago

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MArishka [77]

Answer:

Step-by-step explanation:

you multiply 150*4 then divide that by 10 and that's your answer

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3 years ago

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