Answer:
A = 15 a²b²c² square units
Step-by-step explanation:
Area of a rectangle = LW
A = (1.5abc)(10abc)
A = 15 a²b²c² square units
I think it may be 1,680B but I'm not too sure...
1 yard = 3 feet
2.5×18=45 feet
45÷3= 15 yards
Answer:
(a) 1/6
(b) 1/2
(c) 1/3
Step-by-step explanation:
There are 6 possible outcomes.
(a) The number is 2: only 1 outcome out of 6, hence 1/6
(b) The number is even: {2, 4, 6} - 3 outcomes out of 6, hence 3/6 = 1/2
(c) The number is greater than four: {5, 6} - 2 outcomes out of 6, hence 2/6 = 1/3
Part A: each tricycle has three wheels, so with 48 wheels the number of tricycles was a =48/3=16 tricycles.
t=w/3 (the number of tricycles is the number of wheels divided by 3)
Part B:
The number of seats:
24=b+a (so b=24-a)
The number of seats is the sum of one seat per bicycle and one seat per a tricycle
also, 61=2a+3b (the number of wheels)
So we have:
24=b+a
b=24-a
We can substitute this for b:
61=2a+3(24-a)
and solve:
61=2a+3*24-3a
61=72-a
a=72-61
a=11
There were 11 bicycles!!
and there were 24-11 tricycles, so 13 tricycles.
Part C: each of the bikes has only one front-steering handlebar, so there were a total of 144 vehicles:
a+b+c=144
There were 378 pedals. And the number of pedals is:
2a+2b+4c=378 (the numbers 2,2,4 represent the number of pedals per vehicle)
divide by 2:
a+b+2c=189
Now, we have
a+b+2c=189
and
a+b+c=144
and we can subtract them from each other:
a+b+c-(a+b+2c)=144-189
-c=45
c=45, so there were 45 tandem bicycles!
(this also means that a+b=144-45, that is a+b=99)
now the wheels:
3a+2b+2c=320
Let's substitute c:
3a+2b+90=320
which is
3a+2b=240
We also know that a+b=99, so we can substract this from this equation:
3a+2b+-a-b=240-99
2a+b=141
and again:
2a+b-a-b=141-99
a=42 - there were 42 trycicles!!!
And the bicycles were the rest:
99-42=57 bycicles
