Another way of phrasing this question is this; if only two bills are selected without replacement, what is the probability that at one of the two bills will be a $10 bill:

P(One $10 bill) = P(picking a $10 bill first then another type) + (picking another

type then a $10 bill)

= $\frac{5}{15}*\frac{10}{14}+\frac{10}{15} *\frac{5}{14} = \frac{4}{21}$

6 0

3 years ago

Which expression is equivalent to (5^(3))^(2)

yarga [219]

Answer:

Step-by-step explanation:

$(a^{m} )^{n}$ = $a^{mn}$

$(5^{3} )^{2}$ = $5^{3*2}$ = $5^{6}$ = 15,625

3 0

2 years ago

Ellen is playing a video game in which she captures butterflies. There are 5 butterflies onscreen, but the number of butterflies

vovikov84 [41]

(Each minute+1)((Number of butterflies)^2)

5 0

2 years ago