Answer:

Step-by-step explanation:
All you do is multiply straight across [both denominator and numerator] to arrive at your answer. Then, multiplying two <em>x</em>'s together gives you
. So, with all that being said, you have your answer.
I am joyous to assist you anytime.
The side lengths of triangle are 6 units, 8 units and 10 units.
<u>SOLUTION:
</u>
Given that, we have to find what is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)
We know that, distance between two points
is given by

Now,

259% increase because 6 x 2 is 12 and 3 is the remainder and 3/6 is 50%
Answer:
Far left: constant of proportionality= 3.4
Middle: q=12----COP=3
Far right: COP=4----not proportional