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snow_tiger [21]
3 years ago
6

The sum of the squares of two nonnegative numbers is 327. The product of the two numbers is 101. What is the sum of the two numb

ers?
Mathematics
1 answer:
Verizon [17]3 years ago
8 0
A) x² + y² = 327
B) x * y = 101
Solving equation B for y²
B) y² = 10,201 / x²
Substituting this into equation A)
x² + 10,201 / x² = 327
x^4 + 10,201 = 327x²
x^4  -327x²  + 10,201 = 0
Using the quartic equation calculator: http://www.1728.org/quartic.htm
x1 = 17.090169943749476
x2 = 5.909830056250525
 
x1 * x2 = 101
x1 + x2 = 23


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Answer: she uses 2 eggs for one batch of brownies and 4 eggs for one batch of cookies.

Step-by-step explanation:

Let x represent the number of eggs that she uses for one batch of brownies.

Let y represent the number of eggs that she uses for one batch of cookies.

Last month, she made 2 batches of brownies and 3 batches of cookies. This means that

2x + 3y = 16 - - - - - - - - - -1

The month before, she baked 1 batch of brownies and 1 batch of cookies, which required a total of 6 eggs. This means that

x + y = 6 - - - - - - - - - - - - - 2

Multiplying equation 1 by 1 and equation 2 by 2, it becomes

2x + 3y = 16

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Subtracting, it becomes

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3 years ago
A store sells
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The square has a perimeter of 24 ft. What is the length of each side. Plsssss help
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Step-by-step explanation:

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please show on graph (with x and y coordinates) state where the function x^4-36x^2 is non-negative, increasing, concave up​
babunello [35]

Answer:

y'' =12x^2 -72=0

And solving we got:

x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}

We can find the sings of the second derivate on the following intervals:

(-\infty Concave up

x=-\sqrt{6}, y =-180 inflection point

(-\sqrt{6} Concave down

x=\sqrt{6}, y=-180 inflection point

(\sqrt{6} Concave up

Step-by-step explanation:

For this case we have the following function:

y= x^4 -36x^2

We can find the first derivate and we got:

y' = 4x^3 -72x

In order to find the concavity we can find the second derivate and we got:

y'' = 12x^2 -72

We can set up this derivate equal to 0 and we got:

y'' =12x^2 -72=0

And solving we got:

x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}

We can find the sings of the second derivate on the following intervals:

(-\infty Concave up

x=-\sqrt{6}, y =-180 inflection point

(-\sqrt{6} Concave down

x=\sqrt{6}, y=-180 inflection point

(\sqrt{6} Concave up

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2 years ago
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