The dominant term is -2x⁴.
As X approaches infinite, y is naturally going to be really large as well.
Remember that a number with an even exponent, regardless of whether it's positive or negative, will be positive.
As x approaches infinite, y will approach -2 * ∞, or -∞. Therefore, the end behavior in the positive direction is y=-∞
As x approaches negative infinite, y will approach -2 *∞ again. This is because -∞⁴ = ∞. Therefore, the end behavior in the negative direction is also y=-∞
Basically, due to the dominance of the -2x^4 term, the function will look more or less like a downward facing parabola with a y-intercept of 3.
The mean average difference is not that important, the mean is the only information you need to work out which one has the most words per page. I think the answer is C
Answer:
See below for solution.
Step-by-step explanation:
= 
<u>LHS :-</u>
= 
= 
= 
= 
= 
=> x = 8/3 and y = 1/3
=> <u>Option B</u>
<u></u>
<u></u>
+ 
+ 
= 4 x (∛216)² + (![\sqrt[4]256}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D256%7D)
)³ + 2 x (![\sqrt[5]{243}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B243%7D)
)
= 4 x 36 + 64 + 2 x 3
= 144 + 64 +6
= 144 + 70
= <u>214</u>
Ok, the expression represents the total amount paid because the 4 is the total tax being ADDED to the rest of the expression is 3(26-7). We need to distribute the parentheses by doing: 3*26-3*7. The 3*26 is the three soccer balls multiplied the cost of each ball without the balls being on sale, which is the $26. This brings you to $78. However we then need to do the 3*7, which is the three soccer balls being multiplied by the amount of money you save on each ball being purchased since they're on sale. So that would be $21. Then, $78-$21=$57. $57 is the cost of the three soccer balls without the tax, so we then plug 57 back into the original equation and add 4 to it, since the $4 is the tax. And finally, $57+$4=$61, which is the total amount of money the coach spent on the 3 soccer balls.
For the second part of the equation: Since parentheses comes first in PEMDAS, we need to solve the parentheses first by solving 3(26-7). I've explained how to distribute that in the first explanation above. But basically you just distribute the parentheses using the three, which is 3*26-3*21. You then add four when you finish distributing the equation, since addition comes after parentheses in PEMDAS
