Answer:
1132.8 ml of water
Explanation:
you have an aqueous solution contains 158.2 g KOH per liter
so concentration =158.2/56 = 2.825M
Molarity =2.825
that means you have 2.825 moles of KOH in 1.00L solution
Mass of Soluet(KOH)= 152.8g
Volume of solution= 1.00L
density of solution= 1.13g/cm3 =1.13g/ml
therefore mass of solution = VolumeX density = 1000mL X 1.13g/ml.=1130g
Mass of solvent(water)= mass of solution- mass of solute(KOH)=1130-152.8= 997.2g
Molality= moles of solute/mass of solvent(Kg)
=2.825/(997.2/1000)= 2.832molal
to prepare a 0.250 molal solution of KOH, starting with 100.0ml ofthe orginal solution
0.250*X =2.832 *100
X = 1132.8 ml of water you have to add
air blows at the base of circulation cells from high pressure to low pressure
Answer:
<em>Carb</em><em>on</em><em> </em><em>dio</em><em>xide</em><em> </em>(co2)
<em>Wate</em><em>r</em><em> </em><em>(</em><em>H2O</em><em>)</em>
he total number of each of the atoms on the left and the right are the same thus the reaction equation is balanced.
<h3>What is the law of conservation of mass?</h3>
The law of conservation of mass states that, mass can neither be created nor destroyed. In view of the law of conservation of mass, the total mass of the reactants on the left-hand side must be the same as the total mass of products at the right hand side.
Thus is the total mass of the reactants and the products are not the same, it then follows that the reaction does not demonstrate the law of conservation of mass. In this case, the total number of each of the atoms on the left and the right are the same thus the reaction equation is balanced.
Learn more about conservation of mass:brainly.com/question/13383562
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