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Answer:
If the lac enzyme continues to be produced even in the absence of lactose, the cell will be expending energy unnecessarily and this will be a problem for the supply of energy for other metabolic processes.
If the lac operator gene is dragged to any stretch of DNA, that gene may provide an inadequate reading generating a mutation.
Explanation:
The lac operon is an essential molecule for the transport and metabolism of lactose in microorganisms. This molecule has a fundamental function in the life of these single-celled organisms and must be synthesized immediately when lactose is present in the organism, however, its synthesis must be stopped as soon as the lactose is metabolized, otherwise the cell can spend energy unnecessarily preventing others Metabolic processes take place, which is a big problem if you only have one cell.
In addition, if for some reason, the lac operon gene is dragged on the DNA strand, an incorrect reading of the DNA bases can occur, which can cause mutations.
D is the correct answer to this question. Here is a chart of energy transfer.
<span>A grassland is a biome having predominantly grasses, and some woody shrubs, instead of trees and forests. So, Yes they do.</span>
The answer is 44 chickens and 28 rabbits.
We have a system of two equations.
x - the number of rabbits
y - the number of chickens
Both chicken and rabbit have only 1 head, so the first equation is: x + y = 72.
Since rabbits have 4 legs and chickens 2 legs, the second equation is: 4x + 2y = 200.
Now, let's solve the system:
x + y = 72
4x + 2y = 200
___________
y = 72 - x
⇒ 4x + 2 · (72 - x) = 200
4x + 2 · 72 - 2 · x = 200
4x + 144 - 2x = 200
2x + 144 = 200
2x = 200 - 144
2x = 56
⇒ x = 56 ÷ 2 = 28
So, there are 28 rabbits.
Since
y = 72 - x = 72 - 28 = 44,
there are 44 chickens.
