Treat x^4 as the square of p: x^4 = p^2.
Then x^4 - 5x^2 - 36 = 0 becomes p^2 - 5p - 36 = 0.
This factors nicely, to (p-9)(p+4) = 0. Then p = 9 and p = -4.
Equating 9 and x^2, we find that x=3 or x=-3.
Equating -4 and x^2, we see that there's no real solution.
Show that both x=3 and x=-3 are real roots of x^4 - 5x^2 - 36 = 0.
Answer:
130
Step-by-step explanation:
ABC = 180 - 120 = 60
ACB = 180 - 70 - 60 = 50
ACD = 180 - 50 = 130
I hope I've helped you.
Answer:
Step-by-step explanation:
To solve the expression
first we will multiply -n with each term and then find their products.
When doing multiplication the powers will be added and co-efficient will be multiplied.
Answer:
(8-n=4)/4 click brainliest please and click thanks
Step-by-step explanation:
