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Snowcat [4.5K]
3 years ago
11

Math For test help plz due in 45 mins

Mathematics
2 answers:
EleoNora [17]3 years ago
7 0
It is the third option
Helga [31]3 years ago
4 0

\huge{\underline{\underline{\mathfrak{\red{Answer}}}}}

3rd one✓✓

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Write an equation for your trend line?
Soloha48 [4]
Find two points on the graph that the line crosses through almost perfectly. It looks like (1,10) and (9,1) will do.

Use them to compute the slope:
m = (1 - 10) / (9 - 1)
= -9/8

Then set up the "point-slope form":
y - y0 = m * (x - x0)

You choose some point (x0, y0) that the line crosses through. We already know the line passes through (1,10) pretty well, so let's use that.

x0 = 1
y0 = 10

Now finish plugging into the equation:
y - 10 = -9/8 * (x - 1)

The above equation will work fine for an answer, but let's go a step further and solve for y.

y - 10 = -9/8x + 9/8
y = -9/8x + 9/8 + 10
y = -9/8x + 9/8 + 80/8
y = -9/8x + (9 + 80)/8
y = -9/8x + 89/8
4 0
4 years ago
What the answer asap
Elan Coil [88]
20 qt = 80 c is ur answer. Hope this helps
3 0
3 years ago
Read 2 more answers
Can someone please help me??
butalik [34]

I do believe the answer is D

6 0
3 years ago
PLEASE HELP) Given the function ƒ(x) = x and the function g(x) = x – 4, what does the –4 do to the graph of ƒ(x) to get the grap
SOVA2 [1]

Answer:

C. Translates the graph 4 units downwards

Step-by-step explanation:

The -4 is the y-intercept which brings the graph down four units

5 0
3 years ago
1+Sin/Cos + Cos/1+Sin = 2Sec
Bond [772]

Step-by-step explanation:

Consider the left-hand side:

\dfrac{1+\sin{\theta}}{\cos{\theta}} + \dfrac{\cos{\theta}}{1+\sin{\theta}}

\:\:\:\:= \dfrac{(1+\sin{\theta})^2 + \cos^2{\theta}}{\cos{\theta}(1+\sin{\theta})}

\:\:\:\:=\dfrac{1+2\sin{\theta}+\sin^2{\theta} + \cos^2{\theta}}{\cos{\theta}(1+\sin{\theta})}

\:\:\:\:=\dfrac{2+2\sin{\theta}}{\cos{\theta}(1+\sin{\theta})} =\dfrac{2(1+\sin{\theta})}{\cos{\theta}(1+\sin{\theta})}

\:\:\:\:= \dfrac{2}{\cos{\theta}} = 2\sec{\theta}

7 0
3 years ago
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