Question

A box contains cards number 1-10. A card is drawn at random, without replacement, and a second card is drawn. What is the probability that the first number is a multiple of five and the second number is a multiple of three?

Answer 1

Answer:

Step-by-step explanation:

Total outcome is 10 and favorable outcome is 2 ⇒ the probability that the first number is a multiple of five is $\frac{2}{10}$ = $\frac{1}{5}$

Total outcome is 9 and favorable outcome is 3 ⇒ the probability that the first number is a multiple of three is $\frac{1}{3}$ if first draw was successful, and $\frac{2}{9}$ if the first number was multiple of three.

Answer 2

Answer:

3/50

Step-by-step explanation:

I don’t really know guys