The time taken for radio signal to the earth's surface we shall proceed as follows;
time=(distance)/(speed)
Distance=7.5×10^6 meters
speed=3×10^8 meters/second
therefore:
Time=(7.5×10^6)/(3×10^8)=0.025 seconds
We conclude that it will take the signal 0.025 seconds to reach the surface of the earth.
Step-by-step explanation:
Solution:
(a) is the vertical direction, the force of gravity
on the object (or the wight force: w = Mg ) pulls the crate down while the surface reaction. N. pushes it 103N
rd, as shown:
w = Mg = (20.0kg 9.8m s3 - 196N
N- 196N as well
(b) In the horizontal direction, in the absence of
friction, there are two forces: (F) and the 53-N force. Applying the Newton's 2nd law helps the calculation of the unknown force. F. F - 53N (20.0 kg)(2.5 m 3
F = 103N plz mark me as brainliest
It's rigged
The vertical line test can be used to determine whether a graph represents a function
Answer:
A. x = 1/4
Step-by-step explanation:
Simplify the equation:
(3x^2+1)/(x-1) + x = 4 + 4/(x-1)
(3x^2+1-4)/(x-1) = 4-x
(3x^2-3)/(x-1) = 4-x
Since (3x^2-3) = 3(x^2-1) and x^2-1 = (x+1)(x-1), substitute 3x^2-3 for 3(x+1)(x-1)
3(x+1)(x-1)/(x-1) = 4-x
Cancel (x-1) from the numerator and denominator:
3(x+1) = 4-x
Isolate x:
3(x+1) = 4-x
3x+3 = 4-x
4x = 1
x = 1/4.
x = 1/4 is the only valid solution unless both sides being undefined would count as a valid equation, then x = 1 would also be valid.
