The statements about the local maximums and minimums for the given function which are true include:
- Over the interval [2, 4], the local minimum is –8.
- Over the interval [3, 5], the local minimum is –8.
- Over the interval [1, 4], the local maximum is 0.
<h3>What is Function?</h3>
This is defined as the mathematical entities which assign unique outputs to given inputs and defines a relationship between the two variables.
According the the graph: over the interval [2, 4], the local minimum is –8 because the given minimum point is (3.4, -8) and over the interval [3, 5], the local minimum is –8.
Over the interval [1, 4], the local maximum is 0 and over the interval [3, 5], there is no maximum point hence why it is false.
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A is the answer just took the test
Answer:
Y=s^2/36 and y=5.7;14.3 ft
Step-by-step explanation:
A(s)=s2/36 is the function. A(s) is the aspect ratio, while s is the wingspan. A(s) = 5.7 if one glider has an aspect ratio of 5.7. We'd want to know the glider's wingspan. By replacing A(s) with Y, we get the following equation system:
- Y=s^2/36
- with y = 5.7
- 5.7 = s^2/36
- 5.7*36 = s^2
- √205.2 = s
- 14.3 ft
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
- Terms/Coefficients
- Factoring
<u>Algebra II</u>
- Exponential Rule [Powering]:

- Solving exponential equations
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
<em />
<em />
<em />
<u>Step 2: Solve for </u><em><u>x</u></em>
- Rewrite:

- Set:

- Factor:

- [Division Property of Equality] Divide 3 on both sides:

- [Subtraction Property of Equality] Subtract 3x on both sides:

- [Subtraction Property of Equality] Subtract 6 on both sides:

- [Division Property of Equality] Divide -1 on both sides:

2,3,6 because 2 and 3 cant equal 6