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STALIN [3.7K]
3 years ago
8

Find the equation of the tangent line at the point (0,1) of the graph of the function f(x) = x^3 - 2x + 1 ?​

Mathematics
1 answer:
s2008m [1.1K]3 years ago
7 0

9514 1404 393

Answer:

  y = -2x +1

Step-by-step explanation:

The derivative of the function is ...

  f'(x) = 3x^2 -2

so the slope at x=0 is f'(0) = -2. In slope-intercept form, the equation of the tangent line is ...

  y = -2x +1

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