2 years ago

Find the equation of the tangent line at the point (0,1) of the graph of the function f(x) = x^3 - 2x + 1 ?

1 answer:

7 0

9514 1404 393

Answer:

y = -2x +1

Step-by-step explanation:

The derivative of the function is ...

f'(x) = 3x^2 -2

so the slope at x=0 is f'(0) = -2. In slope-intercept form, the equation of the tangent line is ...

y = -2x +1

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Find the equation of the tangent line at the point (0,1) of the graph of the function f(x) = x^3 - 2x + 1 ?​