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4 years ago

WILL GIVE BRAINLIST PLEASE HELP ME SOMEONE

Mathematics

1 answer:

lara [203]4 years ago

4 0

Answer:

Linear pair postulate

Step-by-step explanation:

Linear pair postulate states that if two angles adjacent to each other form a line, then they are a linear pair and are supplementary.

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Please help me please please please please

andreev551 [17]

Answer:

Step-by-step explanation:

$\frac{y_{2} -y_{1} }{x_{2} -x_{1}}$

lets do (1.5, 3.6) and (2.5, 6)

(6 - 3.6) / (1.5 - 2.5)

put answer in comment and i will mark

please put brainest

5 0

3 years ago

Gina is four years younger than twice David's age. Gina is 18. How old is David?

Sati [7]

Answer:

Step-by-step explanation:

Gina is four years younger so

18+4=22

since its twice davids age

22×2=44

6 0

3 years ago

p is a polynomial of degree 5. p has roots of multiplicity 2 at t=4 and t=0, a root of multiplicity 1 at t=-4, and p(1)=2025. Fi

DENIUS [597]

P(x) = (x^2)(x - 4)^2(x + 4) + some constant(b)
2025 = (1^2)(1 - 4)^2(1 + 4) + b
2025 = 45 + b
b = 1980

Complete Equation:

p(x) = (x^2)(x - 4)^2(x +4) + 1980

or expanded form

p(x) = x^5 - 4x^4 - 16x^3 + 64x^2 + 1980

5 0

3 years ago

Suppose that 60 batteries are shipped to an auto parts store, and that 5 of those are defective. A fleet manager then buys 6 of

PIT_PIT [208]

Answer:

In 8910 ways can at least 4 defective batteries be included in the purchase

Step-by-step explanation:

The order in which the batteries are there is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

4 defective:

4 defective from a set of 5 and 2 non-defective from a set of 60 - 5 = 55. So

$C_{5,4}C_{60,2} = \frac{5!}{1!4!} \times \frac{60!}{2!58!} = 8850$

5 defective:

5 defective from a set of 5 and 1 non-defective from a set of 60 - 5 = 55. So

$C_{5,5}C_{60,5} = \frac{5!}{0!5!} \times \frac{60!}{1!59!} = 60$

In how many ways can at least 4 defective batteries be included in the purchase?

$T = 8850 + 60 = 8910$

In 8910 ways can at least 4 defective batteries be included in the purchase

8 0

3 years ago

13 + 2(50 - 2) = 29

allsm [11]

Hey!

-------------------------------------------------

Steps To Solve:

Remember to follow PEMDAS when solving.

13 + 2(50 - 2) = 29

~Solve what's in parenthesis

13 + 2(48) = 29

~Multiply

13 + 96 = 29

~Add

109 ≠ 29

-------------------------------------------------

Hence, the equation is false.

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Hope This Helped! Good Luck!

7 0

3 years ago

WILL GIVE BRAINLIST PLEASE HELP ME SOMEONE​

WILL GIVE BRAINLIST PLEASE HELP ME SOMEONE