All categories

2 years ago

Answer this if you can boom bam bop

Mathematics

2 answers:

Over [174]2 years ago

7 0

Answer:

60.00

Step-by-step explanation:

20% of 60 = 12 which equals the amount of money Peter has.

So, at $60, he has 20% and $12.00

andrew11 [14]2 years ago

4 0

Answer:

D. $60

Step-by-step explanation:

<u>If the amount is equal and each is 20% = $12, then total is:</u>

100% = 20%*5 = $12*5 = $60

Correct choice is D

You might be interested in

CORRECT ONE GETS BRAINLIEST!!!!!!

Elza [17]

Answer:

CD = 11 units

Step-by-step explanation:

<em>See the drawing attached</em>

<h3>Given</h3>

C is midpoint of AB
B is between A and D
AD = 15
BD = 7
Find CD

<h3>Solution</h3>

CD = CB + BD =
1/2AB + BD =
1/2(AD - BD) + BD =
1/2(15 - 7) + 7 =
1/2(8) + 7 =
4 + 7 =
11

3 0

2 years ago

Solve by using substitution or elimination by addition.<br>6x - 5y = 72<br>2x + 6y = -22

vazorg [7]

Use a calculator called symbolab.com

8 0

2 years ago

Read 2 more answers

Which equation is the inverse of y = 16x2 + 1?

Llana [10]

Answer:

$y=\frac{\sqrt{x-1} }{4}$

Step-by-step explanation:

The given equation is

$y=16x^2+1$

For this function to have an inverse, we must restrict the domain, say $x\ge0$

We interchange x and y to get,

$x=16y^2+1$

We now make y the subject to get;

$x-1=16y^2$

We divide through by 16 to get;

$\frac{x-1}{16}=y^2$

We now take the square root of both sides to get;

$\pm \sqrt{\frac{x-1}{16}}=y$

$y=\pm \frac{\sqrt{x-1} }{4}$

Since $x\ge 0$ , the inverse function is

$y=\frac{\sqrt{x-1} }{4}$

6 0

2 years ago

If a,b,c and d are positive real numbers such that logab=8/9, logbc=-3/4, logcd=2, find the value of logd(abc)

Eva8 [605]

We can expand the logarithm of a product as a sum of logarithms:

$\log_dabc=\log_da+\log_db+\log_dc$

Then using the change of base formula, we can derive the relationship

$\log_xy=\dfrac{\ln y}{\ln x}=\dfrac1{\frac{\ln x}{\ln y}}=\dfrac1{\log_yx}$

This immediately tells us that

$\log_dc=\dfrac1{\log_cd}=\dfrac12$

Notice that none of $a,b,c,d$ can be equal to 1. This is because

$\log_1x=y\implies1^{\log_1x}=1^y\implies x=1$

for any choice of $y$ . This means we can safely do the following without worrying about division by 0.

$\log_db=\dfrac{\ln b}{\ln d}=\dfrac{\frac{\ln b}{\ln c}}{\frac{\ln d}{\ln c}}=\dfrac{\log_cb}{\log_cd}=\dfrac1{\log_bc\log_cd}$

so that

$\log_db=\dfrac1{-\frac34\cdot2}=-\dfrac23$

Similarly,

$\log_da=\dfrac{\ln a}{\ln d}=\dfrac{\frac{\ln a}{\ln b}}{\frac{\ln d}{\ln b}}=\dfrac{\log_ba}{\log_bd}=\dfrac{\log_db}{\log_ab}$

so that

$\log_da=\dfrac{-\frac23}{\frac89}=-\dfrac34$

So we end up with

$\log_dabc=-\dfrac34-\dfrac23+\dfrac12=-\dfrac{11}{12}$

###

Another way to do this:

$\log_ab=\dfrac89\implies a^{8/9}=b\implies a=b^{9/8}$

$\log_bc=-\dfrac34\implies b^{-3/4}=c\implies b=c^{-4/3}$

$\log_cd=2\implies c^2=d\implies\log_dc^2=1\implies\log_dc=\dfrac12$

Then

$abc=(c^{-4/3})^{9/8}c^{-4/3}c=c^{-11/6}$

So we have

$\log_dabc=\log_dc^{-11/6}=-\dfrac{11}6\log_dc=-\dfrac{11}6\cdot\dfrac12=-\dfrac{11}{12}$

4 0

2 years ago

16 more than s is at most −80.

polet [3.4K]

Answer:

s + 16 ≤ −80

Step-by-step explanation:

Analyze each part in the word equation:

"16 more than s" s increased by 16; s + 16

"is at most" is equal to or less than; ≤

"−80" -80

Put the equation back together:

s + 16 ≤ −80

4 0

3 years ago