Answer:
z = x^3 +1
Step-by-step explanation:
Noting the squared term, it makes sense to substitute for that term:
z = x^3 +1
gives ...
16z^2 -22z -3 = 0 . . . . the quadratic you want
_____
<em>Solutions derived from that substitution</em>
Factoring gives ...
16z^2 -24z +2z -3 = 0
8z(2z -3) +1(2z -3) = 0
(8z +1)(2z -3) = 0
z = -1/8 or 3/2
Then we can find x:
x^3 +1 = -1/8
x^3 = -9/8 . . . . . subtract 1
x = (-1/2)∛9 . . . . . one of the real solutions
__
x^3 +1 = 3/2
x^3 = 1/2 = 4/8 . . . . . . subtract 1
x = (1/2)∛4 . . . . . . the other real solution
The complex solutions will be the two complex cube roots of -9/8 and the two complex cube roots of 1/2.
Answer:
12a³+2a²+23a+18
Step-by-step explanation:
(3a+2)(4a²-2a+9)=
12a³-6a²+27a+8a²-4a+18=
12a³+2a²+23a+18
If you need more explanation, reply to this answer.
step-by-step.
x
3
+10=15
Step 1: Simplify both sides of the equation.
1
3
x+10=15
Step 2: Subtract 10 from both sides.
1
3
x+10−10=15−10
1
3
x=5
Step 3: Multiply both sides by 3.
3*(
1
3
x)=(3)*(5)
x=15
Answer:
x=15
Answer:
C
Step-by-step explanation:
2 3/4 divided by 1/4
is
2 3/4 multiplied by 4/1
which is (2+3/4)*4 = 2*4 + 3/4*4 = 8+3 =<em>11</em>
