Question

1.Given the function f(x) = -2c + cx - x^2? and f^-1(5) = -1, find c

Answer 1

Here we have a quadratic function and we want to find the value of a constant with a given restriction.

We will find that c = 8.

So we have the function:

$f(x) = -2c + cx - x^2$

We know that:

$f(5)^{-1} = -1 = \frac{1}{-2c + c\cdot 5 - (5)^2}$

Notice that the above equation means that:

$-2c + c\cdot5 - (5)^2 = -1$

Then we just need to solve the above equation for c:

$-2c + 5c - (5)^2 = -1\\\\(-2 + 5)\cdot c - 25 = -1\\\\3\cdot c = -1 + 25\\\\3\cdot c = 24\\\\c = 24/3 = 8$

So we found that the value of c is 8.

This means that the function is:

$f(x) = -16 + 8\cdot x - x^2$

You can see the graph below:

If you want to learn more, you can read:

brainly.com/question/24215686

Answer 2

Given the function f(x)=-2c+cx-x-x<2 you would simply the function to fill out the graph