What is the formula for mortgages?

Mathematics

1 answer:

professor190 [17]3 years ago

7 0

Answer:

Loan payment = Loan amount / Discount factor

Number of Periodic Payments (n) = Payments per year times number of years. Periodic Interest Rate (i) = Annual rate divided by number of payments per. Discount Factor (D) = {[(1 + i) ^n] - 1} / [i(1 + i)^n]

Step-by-step explanation:

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Complete the square of x squared -2/5 x

erica [24]

$\bf \begin{array}{cccccllllll}
{{ a}}^2& + &2{{ a}}{{ b}}&+&{{ b}}^2\\
\downarrow && &&\downarrow \\
{{ a}}&& &&{{ b}}\\
&\to &({{ a}} + {{ b}})^2&\leftarrow 
\end{array}\qquad 
% perfect square trinomial, negative middle term
\begin{array}{cccccllllll}
{{ a}}^2& - &2{{ a}}{{ b}}&+&{{ b}}^2\\
\downarrow && &&\downarrow \\
{{ a}}&& &&{{ b}}\\
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as you can see above... notice the middle term, in a perfect square trinomial, the middle term is, 2 times the guy on the left, without the exponent, and times the guy on the right

so.. .what we have here ... let's see yours is $\bf x^2-\cfrac{2}{5}x\implies x^2-\cfrac{2}{5}x+\boxed{?}^2$

so.. we have a missing guy there, the guy on the right hmm what the dickens would that be anyway?

well... let us use the middle guy $\bf 2\cdot x\cdot \boxed{?}=\cfrac{2}{5}x\implies \boxed{?}=\cfrac{2x}{10x}\implies \boxed{?}=\cfrac{1}{5}$

aha ... there's our guy on the right.... so now we know is 1/5

now... let us call or very good friend Mr Zero, 0

if we "add" whatever, we also have to "subtract" whatever, since all we're really doing is, borrowing from 0

thus $\bf x^2-\cfrac{2}{5}x\implies x^2-\cfrac{2}{5}x\quad +\left( \cfrac{1}{5} \right)^2\quad -\left( \cfrac{1}{5} \right)^2
\\\\\\
\left[ x^2-\cfrac{2}{5}x +\left( \cfrac{1}{5} \right)^2 \right]-\left( \cfrac{1}{5} \right)^2\implies \left( x-\cfrac{1}{5} \right)^2 - \cfrac{1^2}{5^2}
\\\\\\
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14-7=7
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-42 is your answer.

Hoped I helped!

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√169

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